请写一个用概率计算圆周率的程序，用python语言，java语言，C++语言分别写一下，谢谢你

Python代码实现：

import random

def estimate_pi(n):
    num_point_circle = 0
    num_point_total = 0
    for _ in range(n):
        x = random.uniform(0, 1)
        y = random.uniform(0, 1)
        distance = x**2 + y**2
        if distance <= 1:
            num_point_circle += 1
        num_point_total += 1
    return 4 * num_point_circle / num_point_total

print(estimate_pi(10000))

Java代码实现：

import java.util.Random;

public class EstimatePi {
    public static double estimatePi(int n) {
        int numPointCircle = 0;
        int numPointTotal = 0;
        Random rand = new Random();
        for (int i = 0; i < n; i++) {
            double x = rand.nextDouble();
            double y = rand.nextDouble();
            double distance = x * x + y * y;
            if (distance <= 1) {
                numPointCircle++;
            }
            numPointTotal++;
        }
        return 4.0 * numPointCircle / numPointTotal;
    }

    public static void main(String[] args) {
        System.out.println(estimatePi(10000));
    }
}

C++代码实现：

#include <iostream>
#include <random>

double estimate_pi(int n) {
    int num_point_circle = 0;
    int num_point_total = 0;
    std::random_device rd;
    std::mt19937 gen(rd());
    std::uniform_real_distribution<double> dis(0.0, 1.0);
    for (int i = 0; i < n; i++) {
        double x = dis(gen);
        double y = dis(gen);
        double distance = x * x + y * y;
        if (distance <= 1) {
            num_point_circle++;
        }
        num_point_total++;
    }
    return 4.0 * num_point_circle / num_point_total;
}

int main() {
    std::cout << estimate_pi(10000) << std::endl;
    return 0;
}