首页for (let j = 1; j < sumlist.length; j++) { sum2 = sumlist[length - 2]

for (let j = 1; j < sumlist.length; j++) { sum2 = sumlist[length - 2]

时间: 2024-05-25 16:18:49 浏览: 46

scientist:一个Node.js库，用于仔细重构生产中的关键路径

科学家目录这个怎么运作因此，您只是重构了一大堆代码，所有测试都通过了。您完全有信心将其投入生产。正确的？实际上，没有那么多。无论是较差的测试覆盖率，还是重构的代码非常关键，有时您都需要更多的保证。科学家让您将重构代码与实际代码一起运行，比较输出并在未按预期返回时记录日志。它很大程度上基于GitHub的宝石。让我们来看一个例子。从以下代码开始： const sumList = ( arr ) => { let sum = 0 ; for ( var i of arr ) { sum += i ; } return sum ; } ; 让我们将其重构为： const sumList = ( arr ) => { return _ . reduce ( arr , ( sum , i ) => sum + i ) ; } ; 要进行

+ sumlist[length - 1]; sumlist.push(sum2); length = sumlist.length; if (length === n) { return sumlist[length - 1]; } } This code is incomplete as it is missing the increment statement for the variable j in the for loop. It should be updated to: for (let j = 1; j < sumlist.length; j++) { sum2 = sumlist[length - 2] + sumlist[length - 1]; sumlist.push(sum2); length = sumlist.length; if (length === n) { return sumlist[length - 1]; } } This code is calculating the Fibonacci sequence and returning the nth number in the sequence, where n is the input parameter. It does this by initializing an array with the first two numbers in the sequence (0 and 1), and then iterating through the array, adding the two previous numbers together to generate the next number in the sequence. It continues to do this until the length of the array matches the input parameter, at which point it returns the last number in the array.

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