def getRobotHandles(youBot): # (1) get handles of four wheels -------------------------------- wheel_handle = [-1, -1, -1, -1] # front left, rear left, rear right, front right wheel_handle = [-1, -1, -1, -1] objectName = ['fl', 'rl', 'rr', 'fr'] for i in range(4): objectName[i] = '/youBot/rollingJoint_' + objectName[i] wheel_handle[i] = sim.getObject(objectName[i]) if (wheel_handle[i] != -1): print('get object ' + objectName[i] + ' ok.') # (2) get handles of five arm joints------------------------------- arm_joints_handle = [-1, -1, -1, -1, -1] # 使用列表保存多个关节的句柄 for i in range(0, 5): arm_joints_handle[i] = sim.getObject('/youBot/youBotArmJoint' + str(i)) if (arm_joints_handle[i] != -1): print('get object /youBot/ youBotArmJoint ' + str(i) + ' ok.')这段代码出现了缩进错误，要怎么解决

缩进错误可以通过检查代码中的空格和制表符来解决。在Python中，缩进非常重要，因为它们用于指示代码块的开始和结束。建议使用统一的缩进方式，可以全部使用空格或者全部使用制表符，不要混用。

在这段代码中，第二个for循环的缩进似乎有问题。建议将其缩进量调整为与第一个for循环相同的缩进量。代码示例如下：

def getRobotHandles(youBot):
    # (1) get handles of four wheels --------------------------------
    wheel_handle = [-1, -1, -1, -1]  # front left, rear left, rear right, front right
    wheel_handle = [-1, -1, -1, -1]
    objectName = ['fl', 'rl', 'rr', 'fr']
    for i in range(4):
        objectName[i] = '/youBot/rollingJoint_' + objectName[i]
        wheel_handle[i] = sim.getObject(objectName[i])
        if (wheel_handle[i] != -1):
            print('get object ' + objectName[i] + ' ok.')
    
    # (2) get handles of five arm joints-------------------------------
    arm_joints_handle = [-1, -1, -1, -1, -1]    # 使用列表保存多个关节的句柄
    for i in range(0, 5):
        arm_joints_handle[i] = sim.getObject('/youBot/youBotArmJoint' + str(i))
        if (arm_joints_handle[i] != -1):
            print('get object /youBot/ youBotArmJoint ' + str(i) + ' ok.')

注意，第二个for循环的缩进量已经与第一个for循环相同了。