c语言坦克走迷宫小游戏

以下是C语言键盘控制走迷宫小游戏的代码，供您参考：

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <windows.h>

#define ROW 10
#define COL 10

int map[ROW][COL] = {
    {0,0,0,0,0,0,0,0,0,0},
    {0,1,1,0,1,1,1,0,1,0},
    {0,1,1,0,1,1,1,0,1,0},
    {0,1,1,1,1,0,0,1,1,0},
    {0,1,0,0,0,1,1,1,1,0},
    {0,1,1,1,0,1,1,1,1,0},
    {0,1,0,1,1,1,0,1,1,0},
    {0,1,0,0,0,1,0,0,1,0},
    {0,0,1,1,1,1,1,1,1,0},
    {0,0,0,0,0,0,0,0,0,0}
};

void draw_map();
void gotoxy(int x, int y);
void move(int *x, int *y);

int main()
{
    int x = 1, y = 1;
    draw_map();
    while (map[8][8] != 2) {
        move(&x, &y);
        draw_map();
    }
    printf("\nCongratulations! You win!\n");
    return 0;
}

void draw_map()
{
    system("cls");
    for (int i = 0; i < ROW; i++) {
        for (int j = 0; j < COL; j++) {
            if (map[i][j] == 0) {
                printf("#");
            } else if (map[i][j] == 1) {
                printf(" ");
            } else if (map[i][j] == 2) {
                printf("@");
            }
        }
        printf("\n");
    }
}

void gotoxy(int x, int y)
{
    COORD pos = {x, y};
    HANDLE hOut = GetStdHandle(STD_OUTPUT_HANDLE);
    SetConsoleCursorPosition(hOut, pos);
}

void move(int *x, int *y)
{
    char ch = getch();
    switch (ch) {
        case 'w':
            if (map[*y-1][*x] != 0) {
                map[*y][*x] = 1;
                *y -= 1;
                map[*y][*x] = 2;
            }
            break;
        case 's':
            if (map[*y+1][*x] != 0) {
                map[*y][*x] = 1;
                *y += 1;
                map[*y][*x] = 2;
            }
            break;
        case 'a':
            if (map[*y][*x-1] != 0) {
                map[*y][*x] = 1;
                *x -= 1;
                map[*y][*x] = 2;
            }
            break;
        case 'd':
            if (map[*y][*x+1] != 0) {
                map[*y][*x] = 1;
                *x += 1;
                map[*y][*x] = 2;
            }
            break;
        default:
            break;
    }
}