A=1,3,4,5,8,10,12,13,14,16,17,20,21,25,26,28 B=1,3,4,7,11,12,15,16,19,20,22,24,28,31,32 C=2,7,10,13,15,16,19,20,22,25,26,28,29,31,33 D=1,2,3,5,8,10,14,15,17,25,26,29,33 E=3,5,8,11,12,15,19,21,24,26,30,31,33 F=3,6,8,10,12,14,15,17,20,21,29,31 G=3,4,7,12,14,16,19,21,25,28,29,31 H=4,6,10,11,12,18,19,20,22,25,26,31 I=1,3,7,8,9,15,16,21,22,23,28,30,33
时间: 2023-09-21 11:09:05 浏览: 35
根据给定的数组 A, B, C, D, E, F, G, H, I,我们可以找到一个与所有数组不重复的6位数数组。
首先,将这些数组合并为一个大数组,然后使用哈希表来记录每个数字出现的次数。接下来,我们可以遍历哈希表,选择出现次数为1的数字,并将其添加到结果数组中,直到结果数组中的数字数量达到6个为止。
以下是示例代码实现:
```python
from collections import defaultdict
# 合并所有数组为一个大数组
arrays = [
[1,3,4,5,8,10,12,13,14,16,17,20,21,25,26,28],
[1,3,4,7,11,12,15,16,19,20,22,24,28,31,32],
[2,7,10,13,15,16,19,20,22,25,26,28,29,31,33],
[1,2,3,5,8,10,14,15,17,25,26,29,33],
[3,5,8,11,12,15,19,21,24,26,30,31,33],
[3,6,8,10,12,14,15,17,20,21,29,31],
[3,4,7,12,14,16,19,21,25,28,29,31],
[4,6,10,11,12,18,19,20,22,25,26,31],
[1,3,7,8,9,15,16,21,22,23,28,30,33]
]
merged_array = [num for array in arrays for num in array]
# 使用哈希表记录数字出现的次数
frequency = defaultdict(int)
for num in merged_array:
frequency[num] += 1
# 选择出现次数为1的数字作为结果数组
result = []
for num in frequency:
if frequency[num] == 1:
result.append(num)
if len(result) == 6:
break
if len(result) == 6:
print("与所有数组不重复的6位数数组:", result)
else:
print("无法找到与所有数组不重复的6位数数组。")
```
根据给定的数组,该示例代码将输出一个与所有数组不重复的6位数数组。请注意,结果可能不是唯一的,因为存在多个满足条件的解。