nsnumber属性+1怎么写
时间: 2024-01-24 18:01:45 浏览: 105
对于Objective-C中的NSNumber类型的属性,如果想要将其加1,可以使用以下代码:
```objective-c
self.numberProperty = [NSNumber numberWithInt:[self.numberProperty intValue]+1];
```
其中,`intValue`方法可以将NSNumber类型的属性转换成普通的int类型,然后进行加1操作,再将其转换回NSNumber类型,赋值给原属性。
相关问题
nsnumber 装string
将NSNumber类型转换为NSString类型,可以使用NSNumber提供的`stringValue`方法,示例如下:
```objective-c
NSNumber *number = @123;
NSString *string = [number stringValue];
```
这里将NSNumber类型的number对象转换为NSString类型的string对象,使用`stringValue`方法获取数值的字符串表示形式。如果需要将NSNumber类型的属性装换为NSString类型,可以使用类似的方法,示例如下:
```objective-c
NSNumber *number = self.numberProperty;
NSString *string = [number stringValue];
```
这里将self对象的numberProperty属性转换为NSString类型的string对象,同样使用`stringValue`方法。
写一个iOS 端 蓝牙连接发送消息的代码
### 回答1:
以下是一个简单的iOS蓝牙连接发送消息的代码示例:
1. 导入CoreBluetooth库
```Swift
import CoreBluetooth
```
2. 声明并初始化CentralManager和Peripheral对象
```Swift
var centralManager: CBCentralManager!
var peripheral: CBPeripheral!
```
3. 初始化CBCentralManager
```Swift
centralManager = CBCentralManager(delegate: self, queue: nil)
```
4. 扫描周围的蓝牙设备
```Swift
centralManager.scanForPeripherals(withServices: nil, options: nil)
```
5. 处理扫描到的蓝牙设备
```Swift
func centralManager(_ central: CBCentralManager, didDiscover peripheral: CBPeripheral, advertisementData: [String : Any], rssi RSSI: NSNumber) {
if peripheral.name == "Your Bluetooth Device Name" {
self.peripheral = peripheral
self.peripheral.delegate = self
centralManager.connect(peripheral, options: nil)
}
}
```
6. 处理连接成功的回调函数
```Swift
func centralManager(_ central: CBCentralManager, didConnect peripheral: CBPeripheral) {
print("Connected to: \(peripheral.name ?? "Unknown Device")")
peripheral.discoverServices(nil)
}
```
7. 处理发现服务的回调函数
```Swift
func peripheral(_ peripheral: CBPeripheral, didDiscoverServices error: Error?) {
guard let services = peripheral.services else { return }
for service in services {
print("Service found with UUID: \(service.uuid)")
peripheral.discoverCharacteristics(nil, for: service)
}
}
```
8. 处理发现特征的回调函数
```Swift
func peripheral(_ peripheral: CBPeripheral, didDiscoverCharacteristicsFor service: CBService, error: Error?) {
guard let characteristics = service.characteristics else { return }
for characteristic in characteristics {
print("Characteristic found with UUID: \(characteristic.uuid)")
}
}
```
9. 发送消息
```Swift
func sendMessage() {
let message = "Hello, World!"
guard let data = message.data(using: .utf8) else { return }
if let characteristic = peripheral.services?.first?.characteristics?.first {
peripheral.writeValue(data, for: characteristic, type: .withResponse)
}
}
```
以上是基本的蓝牙连接和发送消息的代码示例,具体实现可以根据实际需求进行修改。
### 回答2:
iOS 端蓝牙连接发送消息的代码如下:
1. 首先,需要导入CoreBluetooth框架。在代码中导入`CoreBluetooth`库。
```swift
import CoreBluetooth
```
2. 创建一个蓝牙中心管理器对象来扫描并连接蓝牙外设。
```swift
class BluetoothManager: NSObject, CBCentralManagerDelegate {
var centralManager: CBCentralManager!
override init() {
super.init()
centralManager = CBCentralManager(delegate: self, queue: nil)
}
func centralManagerDidUpdateState(_ central: CBCentralManager) {
if central.state == .poweredOn {
// 蓝牙已打开,可以开始扫描和连接外设
central.scanForPeripherals(withServices: nil, options: nil)
}
}
func centralManager(_ central: CBCentralManager, didDiscover peripheral: CBPeripheral,
advertisementData: [String : Any], rssi RSSI: NSNumber) {
// 发现外设,可以根据名称或其他信息过滤
if peripheral.name == "YourPeripheralName" {
// 停止扫描并连接外设
central.stopScan()
central.connect(peripheral, options: nil)
}
}
func centralManager(_ central: CBCentralManager, didConnect peripheral: CBPeripheral) {
// 已成功连接外设,可以开始进行数据通信
peripheral.delegate = self
peripheral.discoverServices(nil)
}
}
```
3. 创建一个外设代理类来处理外设的操作。
```swift
extension BluetoothManager: CBPeripheralDelegate {
func peripheral(_ peripheral: CBPeripheral, didDiscoverServices error: Error?) {
guard let services = peripheral.services else { return }
for service in services {
peripheral.discoverCharacteristics(nil, for: service)
}
}
func peripheral(_ peripheral: CBPeripheral, didDiscoverCharacteristicsFor service: CBService, error: Error?) {
guard let characteristics = service.characteristics else { return }
for characteristic in characteristics {
if characteristic.properties.contains(.write) {
// 发送消息的特征
let message = "你好,蓝牙设备!"
let data = message.data(using: .utf8)
peripheral.writeValue(data!, for: characteristic, type: .withoutResponse)
}
}
}
}
```
4. 在你的ViewController或AppDelegate中实例化蓝牙管理器类。
```swift
let bluetoothManager = BluetoothManager()
```
上述代码可以实现以下功能:
1. 初始化蓝牙中心管理器;
2. 扫描并过滤外设;
3. 连接外设,并发现外设的服务和特征;
4. 发送消息给外设。
请根据实际情况进行相应更改,例如替换`"YourPeripheralName"`为要连接的外设名称,以及根据需要使用其他特征的属性和值。
### 回答3:
在iOS端,蓝牙通信主要通过CoreBluetooth框架来实现。下面是一个简单的示例代码,用于实现蓝牙连接并发送消息:
首先,需要在项目中导入CoreBluetooth框架,并在需要使用蓝牙功能的地方引入`import CoreBluetooth`。
然后,创建一个蓝牙管理器和一个蓝牙特征的全局变量:
```swift
var centralManager: CBCentralManager!
var peripheralDevice: CBPeripheral!
var characteristic: CBCharacteristic!
```
接下来,在需要进行蓝牙通信的地方初始化蓝牙管理器:
```swift
centralManager = CBCentralManager(delegate: self, queue: nil)
```
然后,实现CBCentralManagerDelegate代理方法,用于处理蓝牙状态的变化以及扫描到的外设:
```swift
extension ViewController: CBCentralManagerDelegate {
func centralManagerDidUpdateState(_ central: CBCentralManager) {
switch central.state {
case .poweredOn:
central.scanForPeripherals(withServices: nil, options: nil)
default:
print("蓝牙不可用")
}
}
func centralManager(_ central: CBCentralManager, didDiscover peripheral: CBPeripheral, advertisementData: [String : Any], rssi RSSI: NSNumber) {
// 扫描到外设后的处理逻辑
if peripheral.name == "设备名" { // 根据设备名过滤外设
peripheralDevice = peripheral
peripheralDevice.delegate = self
centralManager.connect(peripheralDevice, options: nil)
}
}
func centralManager(_ central: CBCentralManager, didConnect peripheral: CBPeripheral) {
peripheralDevice.discoverServices(nil)
}
}
```
然后,实现CBPeripheralDelegate代理方法,用于处理服务和特征的发现以及数据的发送:
```swift
extension ViewController: CBPeripheralDelegate {
func peripheral(_ peripheral: CBPeripheral, didDiscoverServices error: Error?) {
if let services = peripheral.services {
for service in services {
peripheralDevice.discoverCharacteristics(nil, for: service)
}
}
}
func peripheral(_ peripheral: CBPeripheral, didDiscoverCharacteristicsFor service: CBService, error: Error?) {
if let characteristics = service.characteristics {
for characteristic in characteristics {
if characteristic.uuid == CBUUID(string: "特征UUID") {
self.characteristic = characteristic
break
}
}
}
}
func peripheral(_ peripheral: CBPeripheral, didWriteValueFor characteristic: CBCharacteristic, error: Error?) {
if error != nil {
print("发送消息失败")
} else {
print("发送消息成功")
}
}
}
```
最后,调用发送消息的方法来发送数据:
```swift
func sendMessage(message: String) {
if let data = message.data(using: .utf8) {
peripheralDevice.writeValue(data, for: characteristic, type: .withResponse)
}
}
```
以上是一个简单的iOS端蓝牙连接发送消息的代码示例,具体的逻辑根据项目的需求来进行调整。
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