python代码输出结果:def f(x) if x[1]>=60: return (0,-x[1],x[2]) else: return(1,0,x[2]) n=int(input()) p=[] for i in range(n): s=input(),split() p, append((s[0],int(s[1]),i)) p,sort(key=f) foriin range(n): print(p[i][0])
时间: 2024-02-17 14:03:20 浏览: 15
这段代码存在语法错误,正确的代码应该是:
```
def f(x):
if x[1] >= 60:
return (0, -x[1], x[2])
else:
return (1, 0, x[2])
n = int(input())
p = []
for i in range(n):
s = input().split()
p.append((s[0], int(s[1]), i))
p.sort(key=f)
for i in range(n):
print(p[i][0])
```
这段代码的功能是读入 n 个学生的姓名、分数和编号,然后按照分数从高到低排序,如果分数相同则按照编号从小到大排序,最后输出排序后的学生姓名。其中,函数 f(x) 定义了排序的规则,如果分数大于等于 60 分,则优先级为 0,分数按照从高到低排序,编号按照从小到大排序;否则优先级为 1,分数和编号都不参与排序。
相关问题
def f(x): if x < 0: return -x elif x >= 0 and x < 5: return x + 1 else: return 2*x - 5
This is a Python function that takes a numerical input x and returns a value based on the following conditions:
- If x is less than 0, return the absolute value of x (i.e. -x).
- If x is between 0 (inclusive) and 5 (exclusive), return x.
- If x is greater than or equal to 5, return 2x - 5.
The function is defined using the "def" keyword, followed by the name of the function (in this case, "f") and the input parameter (x). The function body consists of three conditional statements, each of which returns a different value depending on the value of x. The last line of the function, which reads "1", is likely a mistake and should be removed.
def test(a): x=-1 y=-1 for i in range(len(a)): if a[i]=='P': x=i if a[i]=='T': y=i if x == -1 or y == -1: return 0 if x>y: return 0 if x+1 == y: return 0 b=a[:x] if x!=0 else[] c=a[x+1:y] d=a[y+1:] if y!=len(a)-1 else[] if not all(i=='A' for i in b): return 0 if not all(i=='A' for i in c): return 0 if not all(i=='A' for i in d): return 0 return 1 if d == b * len(c) else 0 n=input() for i in range(int(n)): s=input() if test(s) == 1: print('YES') else: print('No') 我的代码哪里出了问题???
你的代码中没有明显的错误,但有一处不一致之处需要注意。在最后输出结果时,你使用了 `'No'` 来表示不满足条件,而原始代码中使用了 `'NO'`。请确保输出的结果与原始代码一致。
以下是修正后的代码:
```python
def test(a):
x = -1
y = -1
for i in range(len(a)):
if a[i] == 'P':
x = i
if a[i] == 'T':
y = i
if x == -1 or y == -1:
return 0
if x > y:
return 0
if x + 1 == y:
return 0
b = a[:x] if x != 0 else []
c = a[x + 1:y]
d = a[y + 1:] if y != len(a) - 1 else []
if not all(i == 'A' for i in b):
return 0
if not all(i == 'A' for i in c):
return 0
if not all(i == 'A' for i in d):
return 0
return 1 if d == b * len(c) else 0
n = input()
for i in range(int(n)):
s = input()
if test(s) == 1:
print('YES')
else:
print('NO')
```
希望这次能够顺利运行!