function dfsWithTimestamp(graph, startNode) visited = zeros(1, length(graph)); visited = zeros(1, length(graph)); timestamp = 1; stack = startNode; timestamps = zeros(1, length(graph)); while ~isempty(stack) node = stack(end); stack(end) = []; if visited(node) == 0 visited(node) = 1; timestamps(node) = timestamp; timestamp = timestamp + 1; % 这里可以根据实际需求进行相应的操作,例如输出节点值 disp(['Visited Node ', num2str(node)]); neighbors = find(graph(node, :)); % 获取相邻节点 for i = length(neighbors):-1:1 if visited(neighbors(i)) == 0 stack(end+1) = neighbors(i); end end end end disp('Timestamps:'); disp(timestamps); end 结束里边有错误visited = zeros(1, length(graph)); 这个问题
时间: 2024-02-14 10:25:15 浏览: 61
非常抱歉,我之前的回答中有误导。我再次检查了您提供的代码,发现确实存在问题。错误出现在第3行和第4行,这两行都是将`visited`数组初始化为全零向量。
您应该只保留其中一行初始化代码,并删除另一行。以下是已经修复的代码示例:
```matlab
function dfsWithTimestamp(graph, startNode)
visited = zeros(1, length(graph));
timestamp = 1;
stack = startNode;
timestamps = zeros(1, length(graph));
while ~isempty(stack)
node = stack(end);
stack(end) = [];
if visited(node) == 0
visited(node) = 1;
timestamps(node) = timestamp;
timestamp = timestamp + 1;
% 这里可以根据实际需求进行相应的操作,例如输出节点值
disp(['Visited Node ', num2str(node)]);
neighbors = find(graph(node, :)); % 获取相邻节点
for i = length(neighbors):-1:1
if visited(neighbors(i)) == 0
stack(end+1) = neighbors(i);
end
end
end
end
disp('Timestamps:');
disp(timestamps);
end
```
请注意,我已经删除了第3行中的重复初始化代码。非常抱歉给您带来困惑,并感谢您的指正。请尝试使用修复后的代码并再次运行。
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