用python3写一段冒泡排序

);
SHA1_R3(e, a, b, c, d, 41);
SHA1_R3(d, e, a, b, c, 42);
SHA1_R3(c, d, e, a, b, 43);
SHA1当然可以，下面是用Python3实现的冒泡排序算法代码：

def bubble_sort(arr):
   _R3(b, c, d, e, a, 44);
    SHA1_R3(a, b, c, d, e n = len(arr)
    # 遍历所有数组元素
    for i in range(n):
        # Last i elements are already in, 45);
    SHA1_R3(e, a, b, c, d, 46);
    SHA1_R3(d, place
        for j in range(0, n-i-1):
            # traverse the array from 0 to n-i-1
 e, a, b, c, 47);
    SHA1_R3(c, d, e, a, b, 48);
            # swap if the element found is greater
            # than the next element
            if arr[j] > arr[j+1]:
                   SHA1_R3(b, c, d, e, a, 49);
    SHA1_R3(a, b, c, arr[j], arr[j+1] = arr[j+1], arr[j]
    return arr

这里使用了两个 d, e, 50);
SHA1_R3(e, a, b, c, d, 51);
SHA1_R3(d, e, a, b, c, 52);
SHA1_R3(c, d, e, a, b,for循环来遍历数组并比较相邻元素，如果前面的元素比后面的元素大，则 53);
SHA1_R3(b, c, d, e, a, 54);
SHA1_R3(a, b交换它们。每次遍历都会将未排序数组中的最大元素放到最后。