乌班图做一个2048 游戏代码C语言
时间: 2023-04-07 07:03:04 浏览: 100
乌班图入门
我可以回答这个问题。以下是一个简单的 C 语言代码,用于实现 2048 游戏:
```c
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define SIZE 4
int board[SIZE][SIZE];
void init_board() {
int i, j;
for (i = 0; i < SIZE; i++) {
for (j = 0; j < SIZE; j++) {
board[i][j] = 0;
}
}
}
void print_board() {
int i, j;
for (i = 0; i < SIZE; i++) {
for (j = 0; j < SIZE; j++) {
printf("%d ", board[i][j]);
}
printf("\n");
}
}
int is_full() {
int i, j;
for (i = 0; i < SIZE; i++) {
for (j = 0; j < SIZE; j++) {
if (board[i][j] == 0) {
return 0;
}
}
}
return 1;
}
void add_random() {
if (is_full()) {
return;
}
int i, j;
do {
i = rand() % SIZE;
j = rand() % SIZE;
} while (board[i][j] != 0);
board[i][j] = (rand() % 2 + 1) * 2;
}
void move_left() {
int i, j, k;
for (i = 0; i < SIZE; i++) {
k = 0;
for (j = 0; j < SIZE; j++) {
if (board[i][j] != 0) {
if (k != j) {
board[i][k] = board[i][j];
board[i][j] = 0;
}
k++;
}
}
for (j = 0; j < SIZE - 1; j++) {
if (board[i][j] == board[i][j + 1]) {
board[i][j] *= 2;
board[i][j + 1] = 0;
}
}
k = 0;
for (j = 0; j < SIZE; j++) {
if (board[i][j] != 0) {
if (k != j) {
board[i][k] = board[i][j];
board[i][j] = 0;
}
k++;
}
}
}
}
int main() {
srand(time(NULL));
init_board();
add_random();
add_random();
print_board();
while (1) {
char c = getchar();
if (c == 'q') {
break;
}
if (c == 'a') {
move_left();
add_random();
print_board();
}
}
return 0;
}
```
这个代码实现了一个简单的 2048 游戏,可以使用 WASD 或方向键来移动方块。
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