<?php // 连接数据库 include "conn.php"; $id = $_POST['id']; $password = $_POST['password']; // 查询admin_personnel表格 $sql="SELECT * FROM admin_personnel WHERE id='$id' AND password='$password'"; $result = $conn->query($sql); // 如果查询结果为空,表示该用户不存在或密码错误 if ($result->num_rows == 0) { echo "Invalid ID or password"; } else { // 获取查询结果中的用户信息 echo "您已成功登录.";} $conn->close(); ?>解决sql语句注入漏洞的问题
时间: 2024-01-06 21:03:38 浏览: 44
要解决SQL注入漏洞,最好的方法是使用预处理语句。这可以通过使用PDO或mysqli扩展来实现。以下是使用PDO的示例代码:
```php
<?php
include "conn.php";
$id = $_POST['id'];
$password = $_POST['password'];
// 使用PDO预处理语句
$sql = "SELECT * FROM admin_personnel WHERE id=? AND password=?";
$stmt = $conn->prepare($sql);
$stmt->execute([$id, $password]);
// 获取查询结果中的用户信息
if ($stmt->rowCount() == 0) {
echo "Invalid ID or password";
} else {
echo "您已成功登录.";
}
$conn->close();
?>
```
使用预处理语句可以确保用户输入的值不会与SQL语句混淆,从而有效地防止SQL注入攻击。
相关问题
dmin_personnel id,int,password,varchar,name,varchar,role,varchar,department,varchar,sex,varchar,email,varchar,telephon,varchar添加admin_personnel表数据,下面代码错误在哪 <?php // 连接数据库 include "conn.php"; // 获取请求参数 $id = $_POST['id']; $name = $_POST['name']; $password = $_POST['password']; $sex = $_POST['sex']; $role = $_POST['role']; $department = $_POST['department']; $email = $_POST['email']; $telephone = $_POST['telephone']; // 创建预处理语句 $stmt = mysqli_prepare($conn, "INSERT INTO admin_personnel (id, name, password, sex, role, department,email,telephone) VALUES (?, ?, ?, ?, ?, ?, ?, ?)"); mysqli_stmt_bind_param($stmt, "isssssss", $id, $name, $password, $sex, $role, $department, $email, $telephone); // 执行预处理语句 if (mysqli_stmt_execute($stmt)) { // 获取插入数据的ID $insert_id = mysqli_insert_id($conn); // 查询插入的数据 $result = mysqli_query($conn, "SELECT * FROM admin_personnel WHERE id=\"$insert_id\""); $row = mysqli_fetch_assoc($result); // 返回响应数据 $response = array( "data" => $row, "meta" => array( "msg" => "用户创建成功", "status" => 201 ) ); echo json_encode($response); } else { // 返回错误信息 $response = array( "meta" => array( "msg" => "用户创建失败", "status" => 500 ) ); echo json_encode($response); } // 关闭连接 mysqli_stmt_close($stmt); mysqli_close($conn); ?>
代码中存在以下错误:
1. admin_personnel 表中的字段名和数据类型没有对应上。
2. $telephone 变量名拼写错误,应该为 $telephon。
修改后的代码如下:
```php
<?php
// 连接数据库
include "conn.php";
// 获取请求参数
$id = $_POST['id'];
$name = $_POST['name'];
$password = $_POST['password'];
$sex = $_POST['sex'];
$role = $_POST['role'];
$department = $_POST['department'];
$email = $_POST['email'];
$telephone = $_POST['telephone'];
// 创建预处理语句
$stmt = mysqli_prepare($conn, "INSERT INTO admin_personnel (id, password, name, role, department, sex, email, telephon) VALUES (?, ?, ?, ?, ?, ?, ?, ?)");
mysqli_stmt_bind_param($stmt, "isssssss", $id, $password, $name, $role, $department, $sex, $email, $telephone);
// 执行预处理语句
if (mysqli_stmt_execute($stmt)) {
// 获取插入数据的ID
$insert_id = mysqli_insert_id($conn);
// 查询插入的数据
$result = mysqli_query($conn, "SELECT * FROM admin_personnel WHERE id=\"$insert_id\"");
$row = mysqli_fetch_assoc($result);
// 返回响应数据
$response = array(
"data" => $row,
"meta" => array(
"msg" => "用户创建成功",
"status" => 201
)
);
echo json_encode($response);
} else {
// 返回错误信息
$response = array(
"meta" => array(
"msg" => "用户创建失败",
"status" => 500
)
);
echo json_encode($response);
}
// 关闭连接
mysqli_stmt_close($stmt);
mysqli_close($conn);
?>
```
帮我找出这段代码的错误并给出正确答案<?php include ("conn.php"); $account = $_POST['account']; $password = $_POST['password']; $sql = "select id from user where account = '$account' and password = '$password'"; $result = $conn->query($sql); if($result->num_row > 0) { session_start(); $_SESSION["user.account"] = $account; $result->free_result(); $conn->close(); header("location:../index.php"); }else { $result->free_result(); $conn->close(); header("location:../login.php?message=用户或密码不一致"); } ?>
这段代码的错误在于if语句中的条件判断应该使用$num_rows而不是$num_row。正确的代码如下:
```
<?php
include ("conn.php");
$account = $_POST['account'];
$password = $_POST['password'];
$sql = "select id from user where account = '$account' and password = '$password'";
$result = $conn->query($sql);
if($result->num_rows > 0) {
session_start();
$_SESSION["user.account"] = $account;
$result->free_result();
$conn->close();
header("location:../index.php");
} else {
$result->free_result();
$conn->close();
header("location:../login.php?message=用户或密码不一致");
}
?>
```
此外,这段代码应该使用参数化查询来避免 SQL 注入攻击。