输入n,求s=1+(1+2)+(1+2+3)+...+(1+2+3+...+n)的值
时间: 2023-12-17 14:02:41 浏览: 46
以下是两种不同语言的代码实现:
C语言实现:
```c
#include <stdio.h>
int main() {
int n, s = 0, i, a, b = 0;
scanf("%d", &n);
if (n < 3) {
printf("Error!\n");
} else {
for (i = 1; i <= n; i++) {
b = 0;
for (a = 1; a <= i; a++) {
b += a;
}
s += b;
}
printf("%d\n", s);
}
return 0;
}
```
Java实现:
```java
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
int n = reader.nextInt();
int i, s = 0, t = 0;
if (n < 3) {
System.out.println("Error!");
} else {
for (i = 1; i <= n; i++) {
t = t + i;
s = s + t;
}
System.out.println(s);
}
}
}
```
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