写一个21点扑克牌的游戏

以下是一个简单的21点扑克牌游戏的示例代码，供您参考：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

// 定义扑克牌面值和花色
char *card_values[] = {"A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K"};
char *card_suits[] = {"♠︎", "♣︎", "♥︎", "♦︎"};

// 定义函数：发牌
int deal_card()
{
    int value = rand() % 13 + 1;  // 随机生成牌面值
    int suit = rand() % 4;        // 随机生成花色
    if (value > 10)
    {
        value = 10;               // J/Q/K 的点数均为10
    }
    else if (value == 1)
    {
        value = 11;               // A 的点数为 11
    }
    return value;
}

// 定义函数：计算点数
int calculate_points(int *cards, int num_cards)
{
    int i, points = 0, num_aces = 0;
    for (i = 0; i < num_cards; i++)
    {
        if (cards[i] == 11)
        {
            num_aces++;           // 统计 A 的数量
        }
        points += cards[i];      // 累加点数
    }
    while (points > 21 && num_aces > 0)
    {
        points -= 10;            // 将 A 视为 1 点
        num_aces--;
    }
    return points;
}

// 主函数
int main()
{
    int player_cards[10], dealer_cards[10];  // 定义两个数组，用于存放玩家和庄家的牌
    int player_points, dealer_points, num_player_cards = 0, num_dealer_cards = 0;
    char choice;
    srand(time(NULL));                       // 初始化随机数种子

    // 发两张牌给玩家和庄家
    player_cards[num_player_cards++] = deal_card();
    dealer_cards[num_dealer_cards++] = deal_card();
    player_cards[num_player_cards++] = deal_card();
    dealer_cards[num_dealer_cards++] = deal_card();

    // 显示玩家的牌和庄家的一张牌
    printf("你的牌：");
    for (int i = 0; i < num_player_cards; i++)
    {
        printf("%s%s ", card_suits[rand() % 4], card_values[player_cards[i] - 1]);
    }
    printf("\n庄家的牌：%s%s\n", card_suits[rand() % 4], card_values[dealer_cards[0] - 1]);

    // 玩家的回合
    while (1)
    {
        player_points = calculate_points(player_cards, num_player_cards);
        printf("你的点数：%d\n", player_points);
        if (player_points > 21)
        {
            printf("你爆了！\n");
            break;
        }
        printf("是否要继续要牌？(y/n)\n");
        scanf(" %c", &choice);
        if (choice == 'y')
        {
            player_cards[num_player_cards++] = deal_card();
        }
        else
        {
            break;
        }
    }

    // 庄家的回合
    dealer_points = calculate_points(dealer_cards, num_dealer_cards);
    while (dealer_points < 17)
    {
        dealer_cards[num_dealer_cards++] = deal_card();
        dealer_points = calculate_points(dealer_cards, num_dealer_cards);
    }
    printf("庄家的牌：");
    for (int i = 0; i < num_dealer_cards; i++)
    {
        printf("%s%s ", card_suits[rand() % 4], card_values[dealer_cards[i] - 1]);
    }
    printf("\n庄家的点数：%d\n", dealer_points);

    // 判断胜负
    if (player_points > 21)
    {
        printf("你输了！\n");
    }
    else if (dealer_points > 21)
    {
        printf("你赢了！\n");
    }
    else if (player_points > dealer_points)
    {
        printf("你赢了！\n");
    }
    else if (player_points < dealer_points)
    {
        printf("你输了！\n");
    }
    else
    {
        printf("平局！\n");
    }

    return 0;
}

在这个程序中，我们使用了随机数生成牌面值和花色，并通过 `deal_card()` 函数来发牌。我们还定义了 `calculate_points()` 函数来计算玩家和庄家的点数，并使用一个循环来进行玩家和庄家的回合。最后，根据点数的比较来判断胜负。

需要注意的是，这只是一个简单的示例程序，实际的21点游戏可能需要更多的规则和玩法。