编写Person类，包含人的姓名和年龄；编写自定义异常类IllegalAgeException，当用户输入的年龄小于0的时候，抛出IllegalAgeException异常，为用户友好提示错误信息。 测试类代码如下： public class TestPersonException { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); try { Person p1 = new Person(scanner.next(), scanner.nextInt()); System.out.println(p1.toString()); } catch (IllegalAgeException e) { System.out.println(e.getMessage()); System.out.println("你输入的年龄为" + e.getAge()); } } }

好的，我理解了你的问题。以下是代码实现：

public class Person {
    private String name;
    private int age;

    public Person(String name, int age) throws IllegalAgeException {
        if (age < 0) {
            throw new IllegalAgeException("年龄不能小于0！");
        }
        this.name = name;
        this.age = age;
    }

    @Override
    public String toString() {
        return "Person{" +
                "name='" + name + '\'' +
                ", age=" + age +
                '}';
    }
}

public class IllegalAgeException extends Exception {
    private int age;

    public IllegalAgeException(String message) {
        super(message);
    }

    public IllegalAgeException(String message, int age) {
        super(message);
        this.age = age;
    }

    public int getAge() {
        return age;
    }
}

public class TestPersonException {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        try {
            Person p1 = new Person(scanner.next(), scanner.nextInt());
            System.out.println(p1.toString());
        } catch (IllegalAgeException e) {
            System.out.println(e.getMessage());
            System.out.println("你输入的年龄为" + e.getAge());
        }
    }
}

在Person类的构造函数中，如果年龄小于0，则抛出IllegalAgeException异常，并且传递友好提示信息到异常类中。在测试类中，我们通过try-catch语句捕获异常，并且输出友好提示信息和用户输入的年龄。