去除上述代码中的方法等高级语言，用最基本的java语言改写上述代码

由于你要求使用最基础的Java语言，我们可以去掉面向对象的部分，只保留基本的数据结构和控制流程。以下是基于原始问题的简单Java代码：

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = scanner.nextInt(), m = scanner.nextInt();
        int[][] board = new int[n][m];

        // 读取初始棋盘
        for (int i = 0; i < n; i++) {
            String[] rowInput = scanner.nextLine().split(" ");
            for (int j = 0; j < m; j++) {
                board[i][j] = Integer.parseInt(rowInput[j]);
            }
        }

        // 检查并消除连续同色棋子
        for (int i = 0; i < n; i++) {
            for (int j = 0; j <= m - 3; j++) {
                if (checkConsecutive(i, j, board)) {
                    removeConsecutive(i, j, m, board);
                }
            }
            for (int j = 0; j <= n - 3; j++) {
                if (checkConsecutive(j, 0, board)) {
                    removeConsecutive(j, 0, m, board);
                }
            }
        }

        // 打印结果
        for (int i = 0; i < n; i++) {
            for (int k = 0; k < m; k++) {
                System.out.print(board[i][k] == 0 ? "0" : board[i][k] + " ");
            }
            System.out.println();
        }
    }

    private static boolean checkConsecutive(int row, int col, int[][] board) {
        int color = board[row][col], count = 1;
        if (color == 0) return false;
        while (count < 3 && col + count < board[0].length && row + count < board.length &&
               board[row + count][col] == color && board[row][col + count] == color) {
            count++;
        }
        return count >= 3;
    }

    private static void removeConsecutive(int row, int col, int boardLength, int[][] board) {
        for (int i = 0; i < 3; i++) {
            board[row + i][col] = 0;
            board[row][col + i] = 0;
        }
    }
}

这个版本的代码去掉了面向对象特性，使用了基本的数组结构和控制结构。