*+satMul2+-+multiplies+by+2,+saturating+to+Tmin+or+Tmax+if+overflow +*+++Examples:+satMul2(0x3000000

根据提供的引用内容，satMul2函数的作用是将输入的数乘以2，并且在溢出时饱和到Tmin或Tmax。下面是实现该函数的代码：

int satMul2(int x) {
  int doubled = x + x;
  int sign = x >> 31;
  int Tmin = 1 << 31;
  int overflow = (doubled >> 31) ^ sign;
  int result = (overflow & (Tmin ^ sign)) | (~overflow & doubled);
  return result;
}

该函数首先将输入的数乘以2，然后判断是否溢出。如果溢出，则将结果饱和到Tmin或Tmax。具体来说，如果溢出，则overflow变量为1，否则为0。如果溢出，则result变量为Tmin或Tmax，具体取决于输入数的符号。如果没有溢出，则result变量为doubled。

相关问题

demo_func = lambda x: x[0] ** 2 + (x[1] - 0.05) ** 2 + x[2] ** 2

The lambda function demo_func takes in a list or tuple of three elements and returns the value of the expression:

x[0] ** 2 * (x[1] - 0.05) ** 2 * x[2] ** 2

The expression first computes the square of the first element of the input list or tuple (x[0] ** 2), then multiplies it by the square of the difference between the second element and 0.05 ((x[1] - 0.05) ** 2), and finally multiplies the result by the square of the third element (x[2] ** 2).

For example, if we call demo_func with the input (2, 0.1, 3), the function will return:

2 ** 2 * (0.1 - 0.05) ** 2 * 3 ** 2 = 18.0

while (*str) { val = val * 2 + (*str++) - '0'; }

This code is a loop that converts a binary string into a decimal integer.

The loop iterates through each character in the string, until it reaches the null terminator (represented by the condition "*str", which means "the value at the memory location pointed to by str").

For each character, the code multiplies the current value of "val" by 2, and then adds the value of the current character (which is converted from ASCII to its corresponding integer value by subtracting the ASCII value of '0').

At the end of the loop, the variable "val" contains the decimal equivalent of the binary string.