未定义标识符printff的解决方法
时间: 2024-05-01 16:15:30 浏览: 17
"未定义标识符printff"的错误通常是因为程序中使用了"printff"这个不存在的函数名。正确的函数名应该是"printf",它是C/C++语言中用于输出信息的函数。如果出现了未定义标识符printff的错误,可以考虑以下几种解决方法:
1. 检查代码中是否真的存在函数名为printff的函数,如果不存在,可以将函数名修改为正确的printf。
2. 检查是否正确包含了stdio.h头文件,该头文件中包含了printf函数的声明。
3. 确认编译器是否支持C/C++标准库,如果不支持,可以尝试更换编译器或者手动实现printf函数。
相关问题
用c语言补全程序,任意输出10个数,输出其中的最小数;最小数与最后面的数互换后,输出10个数,#include<stdi0.h> u0idFt(int ff1,int m) (int j,min,P,t; /*其其*******FILL鬓开其*其其箕箕买箕箦* for(j-1;j<;j++) /*买********FILL**买其著箦买箦其鬌* iF(min>Ff1)min=ff[1: printfF("nmin-d,p-2n”,min,p); /*********FILL*****箕*曇光曇** t-ff[9]: ;FfF[P]=t: printf(输出调换之后的数组:; For(j-0:;j<10;j++)printF("2d",ff[jl); , main() {int a[101,i; For(i=0;i<10;i++) sCanf([“%d”,&a[i1]); for(i=0;i<10;i++) I printF(:&d",a[i]); ft(a,10);}
好的,这是补全后的程序代码:
```c
#include <stdio.h>
void swap(int arr[], int i, int j) {
int temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
void find_min_and_swap(int arr[], int size) {
int i, min_idx = 0;
for (i = 1; i < size; i++) {
if (arr[i] < arr[min_idx]) {
min_idx = i;
}
}
printf("最小数为:%d\n", arr[min_idx]);
swap(arr, min_idx, size - 1);
printf("调换后的数组:\n");
for (i = 0; i < size; i++) {
printf("%2d", arr[i]);
}
printf("\n");
}
int main() {
int arr[10], i;
printf("请输入10个整数:\n");
for (i = 0; i < 10; i++) {
scanf("%d", &arr[i]);
}
printf("输入的数组:\n");
for (i = 0; i < 10; i++) {
printf("%2d", arr[i]);
}
printf("\n");
find_min_and_swap(arr, 10);
return 0;
}
```
程序运行示例:
```
请输入10个整数:
9 3 8 1 7 2 6 5 4 0
输入的数组:
9 3 8 1 7 2 6 5 4 0
最小数为:0
调换后的数组:
9 3 8 1 7 2 6 5 4 0
```
改为matlab语言#pragma region TanVecB_basis double RoutePlan::TanVecB_basis(double u, double *U, int i) { double N_, deta1, deta2, A, B1; struct _Matrix N; Matrix_set_m(&N, 3); Matrix_set_n(&N, 3); Matrix_init_matrix(&N); //printf("i = %d\n", i); (u >= U[i] && u <= U[i + 1]) ? Matrix_write(&N, 0, 0, 1) : Matrix_write(&N, 0, 0, 0); (u >= U[i + 1] && u <= U[i + 2]) ? Matrix_write(&N, 1, 0, 1) : Matrix_write(&N, 1, 0, 0); (u >= U[i + 2] && u <= U[i + 3]) ? Matrix_write(&N, 2, 0, 1) : Matrix_write(&N, 2, 0, 0); //printf("u= %f \n", u); for (int j = 1; j < 3; j++) { for (int k = 0; k < 3 - j; k++) { deta1 = U[i + j + k] - U[i + k]; deta2 = U[i + j + k + 1] - U[i + k + 1]; (deta1 == 0) ? (A = 0) : (A = (u - U[i + k]) / deta1); (deta2 == 0) ? (B1 = 0) : (B1 = (U[i + j + k + 1] - u) / deta2); Matrix_write(&N, k, j, A*Matrix_read(&N, k, j - 1) + B1*Matrix_read(&N, k + 1, j - 1)); //printf("deta1= %f \n", deta1); printf("deta2= %f \n", deta2); } } Matrix_write(&N, 2, 1, 0); Matrix_write(&N, 2, 2, 0); Matrix_write(&N, 1, 2, 0); //printff_matrix(&N); N_ = Matrix_read(&N, 0, 2); //printf(" N_ =%f \n", N_); return N_; } #pragma endregion
function N_ = TanVecB_basis(u, U, i)
N = zeros(3, 3);
N(1, 1) = (u >= U(i) && u <= U(i + 1));
N(2, 1) = (u >= U(i + 1) && u <= U(i + 2));
N(3, 1) = (u >= U(i + 2) && u <= U(i + 3));
for j = 2 : 3
for k = 1 : 3 - j + 1
deta1 = U(i + k + j - 1) - U(i + k - 1);
deta2 = U(i + k + j) - U(i + k);
A = (deta1 == 0) * 0 + (deta1 ~= 0) * (u - U(i + k - 1)) / deta1;
B1 = (deta2 == 0) * 0 + (deta2 ~= 0) * (U(i + k + j) - u) / deta2;
N(k, j) = A * N(k, j - 1) + B1 * N(k + 1, j - 1);
end
end
N(3, 2) = 0;
N(3, 3) = 0;
N(2, 3) = 0;
N_ = N(1, 3);
end
相关推荐
![application/x-rar](https://img-home.csdnimg.cn/images/20210720083606.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![rar](https://img-home.csdnimg.cn/images/20210720083606.png)
![rar](https://img-home.csdnimg.cn/images/20210720083606.png)
![dmg](https://img-home.csdnimg.cn/images/20210720083646.png)