python按列杨辉三角
时间: 2023-11-17 19:01:47 浏览: 79
使用Python可以按列打印杨辉三角,具体实现可以参考以下步骤:
1. 定义一个生成器函数fab,用于生成斐波那契数列。
2. 定义一个生成器函数yanghui_triangles,用于生成杨辉三角。
3. 在主函数中输入要生成的行数N,然后循环调用yanghui_triangles函数,打印出前N行杨辉三角。
示例代码如下(代码类型为Python):
```
def fab(max):
n, a, b = 0, 0, 1
while n < max:
yield b
a, b = b, a + b
n = n + 1
def yanghui_triangles():
a = [1]
while True:
yield a
a = [sum(i) for i in zip([0] + a, a + [0])]
N = int(input("请输入生成行数N: "))
i = 0
for t in yanghui_triangles():
print(t[N-i-1], end=' ')
i += 1
if i == N:
break
```
相关问题
python输出倒立杨辉三角
以下是Python输出倒立杨辉三角的代码示例:
```python
def print_inverted_pascal_triangle(n):
triangle = []
for i in range(n):
row = [1] * (i + 1)
triangle.append(row)
for j in range(1, i):
triangle[i][j] = triangle[i-1][j-1] + triangle[i-1][j]
for row in reversed(triangle):
print(' '.join(map(str, row)))
# 示例调用
print_inverted_pascal_triangle(5)
```
输出结果为:
```
1 4 6 4 1
1 3 3 1
1 2 1
1 1
1
```
Python列表输出杨辉三角形
可以使用以下代码实现:
```
def generate(numRows):
triangle = []
for i in range(numRows):
row = [None for _ in range(i+1)]
row[0], row[-1] = 1, 1
for j in range(1, len(row)-1):
row[j] = triangle[i-1][j-1] + triangle[i-1][j]
triangle.append(row)
return triangle
# 输出杨辉三角形的前6行
tri = generate(6)
for row in tri:
print(row)
```
输出结果:
```
[1]
[1, 1]
[1, 2, 1]
[1, 3, 3, 1]
[1, 4, 6, 4, 1]
[1, 5, 10, 10, 5, 1]
```
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