python自动扫雷代码

以下是一个简单的Python实现自动扫雷的代码示例，仅供参考：

import cv2
import numpy as np
import pyautogui

# 获取游戏窗口的位置
game_window = pyautogui.locateOnScreen('game_window.png', confidence=0.8)
game_window_x, game_window_y, game_window_w, game_window_h = game_window

# 雷区的大小和位置
board_x = game_window_x + 10
board_y = game_window_y + 80
board_w = 320
board_h = 320

# 格子的大小和间隔
cell_size = 16
cell_space = 1

# 定义颜色常量
colors = {
    'unknown': [192, 192, 192],
    'open': [255, 255, 255],
    'flag': [0, 0, 255],
    'mine': [0, 0, 0],
    'digit1': [0, 0, 255],
    'digit2': [0, 128, 0],
    'digit3': [255, 0, 0],
    'digit4': [0, 0, 128],
    'digit5': [128, 0, 0],
    'digit6': [0, 128, 128],
    'digit7': [0, 0, 0],
    'digit8': [128, 128, 128]
}

# 获取游戏窗口的截图
game_image = pyautogui.screenshot(region=(game_window_x, game_window_y, game_window_w, game_window_h))
game_image = np.array(game_image)

# 获取雷区的截图
board_image = game_image[board_y:board_y+board_h, board_x:board_x+board_w]

# 将截图转换为灰度图像
gray_image = cv2.cvtColor(board_image, cv2.COLOR_BGR2GRAY)

# 将灰度图像转换为二值图像
_, binary_image = cv2.threshold(gray_image, 127, 255, cv2.THRESH_BINARY)

# 识别每个格子的状态
board = np.zeros((20, 20), dtype=int)
for i in range(20):
    for j in range(20):
        cell_x = j * (cell_size + cell_space)
        cell_y = i * (cell_size + cell_space)
        cell_image = binary_image[cell_y:cell_y+cell_size, cell_x:cell_x+cell_size]
        cell_color = tuple(board_image[cell_y+cell_size//2, cell_x+cell_size//2])
        if cell_color == tuple(colors['unknown']):
            board[i, j] = 0
        elif cell_color == tuple(colors['open']):
            digit_image = cell_image[2:14, 2:14]
            digit_color = tuple(digit_image[6, 6])
            if digit_color == tuple(colors['digit1']):
                board[i, j] = 1
            elif digit_color == tuple(colors['digit2']):
                board[i, j] = 2
            elif digit_color == tuple(colors['digit3']):
                board[i, j] = 3
            elif digit_color == tuple(colors['digit4']):
                board[i, j] = 4
            elif digit_color == tuple(colors['digit5']):
                board[i, j] = 5
            elif digit_color == tuple(colors['digit6']):
                board[i, j] = 6
            elif digit_color == tuple(colors['digit7']):
                board[i, j] = 7
            elif digit_color == tuple(colors['digit8']):
                board[i, j] = 8
            else:
                board[i, j] = -1
        elif cell_color == tuple(colors['flag']):
            board[i, j] = 9
        elif cell_color == tuple(colors['mine']):
            board[i, j] = -2
        else:
            board[i, j] = -3

# 对雷区进行分析并操作
for i in range(20):
    for j in range(20):
        if board[i, j] == 0:
            # 判断该格子周围是否都已经打开
            if is_all_open(board, i, j):
                # 打开该格子
                open_cell(board, i, j)
        elif board[i, j] > 0:
            # 判断该格子周围已经标记的格子数是否等于周围的雷数
            if is_all_flag(board, i, j):
                # 打开该格子周围的所有未知格子
                open_unknown_cells(board, i, j)
        elif board[i, j] == 9:
            # 判断该格子周围是否都已经打开
            if is_all_open(board, i, j):
                # 取消标记该格子
                unflag_cell(board, i, j)

# 将操作后的雷区状态转换为需要的操作
for i in range(20):
    for j in range(20):
        cell_x = board_x + j * (cell_size + cell_space) + cell_size // 2
        cell_y = board_y + i * (cell_size + cell_space) + cell_size // 2
        if board[i, j] == 0:
            # 点击该格子
            pyautogui.click(cell_x, cell_y)
        elif board[i, j] == 9:
            # 取消标记该格子
            pyautogui.rightClick(cell_x, cell_y)

以上是一个简单的自动扫雷代码示例，其中包含了对雷区截图的处理、状态的识别、分析和操作等。需要注意的是，由于不同的扫雷游戏可能存在差异，因此需要根据具体的游戏进行调整和优化。