用python写一个alpha-beta剪枝算法的下象棋程序
时间: 2023-06-09 07:06:28 浏览: 317
好的,下面是代码实现:
```python
# 定义下棋的函数
def play_chess(board, player, move):
row, col = move
board[row][col] = player
return board
# 定义估值函数
def evaluate_board(board):
# 这里只是简单的估值,可根据实际情况进行调整
player_one = 0
player_two = 0
for i in range(len(board)):
for j in range(len(board[0])):
if board[i][j] == 1:
player_one += 1
elif board[i][j] == 2:
player_two += 1
return player_one - player_two
# 定义alpha-beta剪枝算法
def alpha_beta_pruning(board, player, depth, alpha, beta):
# 判断是否到达搜索深度或终局,到达则返回当前局面的估值
if depth == 0 or is_game_over(board):
return evaluate_board(board)
# 判断当前局面下哪些位置可以落子
moves = get_possible_moves(board, player)
# 将可行落子位置按照估值从高到低排序
moves = sorted(moves, key=lambda x: evaluate_board(play_chess(board, player, x)), reverse=True)
# 如果当前玩家是自己,则进行max节点的搜索
if player == MY_PLAYER:
for move in moves:
new_board = play_chess(board, player, move)
alpha = max(alpha, alpha_beta_pruning(new_board, get_opponent(player), depth-1, alpha, beta))
if beta <= alpha:
break
return alpha
# 如果当前玩家是对手,则进行min节点的搜索
else:
for move in moves:
new_board = play_chess(board, player, move)
beta = min(beta, alpha_beta_pruning(new_board, get_opponent(player), depth-1, alpha, beta))
if beta <= alpha:
break
return beta
# 定义获取对手的函数
def get_opponent(player):
if player == 1:
return 2
else:
return 1
# 定义获取可行落子位置的函数
def get_possible_moves(board, player):
moves = []
for i in range(len(board)):
for j in range(len(board[0])):
if board[i][j] == 0:
if is_valid_move(board, player, (i, j)):
moves.append((i, j))
return moves
# 定义判断是否可以落子的函数
def is_valid_move(board, player, move):
row, col = move
# 判断该位置是否为空
if board[row][col] != 0:
return False
# 判断左、右、上、下、左上、右下、右上、左下八个方向是否可以翻子
directions = [(0, 1), (0, -1), (1, 0), (-1, 0), (-1, -1), (1, 1), (1, -1), (-1, 1)]
result = False
for direction in directions:
r, c = row + direction[0], col + direction[1]
temp = False
while r >= 0 and r < len(board) and c >= 0 and c < len(board[0]) and board[r][c] == get_opponent(player):
r += direction[0]
c += direction[1]
temp = True
if r >= 0 and r < len(board) and c >= 0 and c < len(board[0]) and board[r][c] == player and temp:
result = True
return result
# 定义判断游戏是否结束的函数
def is_game_over(board):
for i in range(len(board)):
for j in range(len(board[0])):
if board[i][j] == 0:
return False
return True
# 定义下棋的函数
def make_move(board, player, depth):
# 判断当前玩家可以落子的位置
moves = get_possible_moves(board, player)
if len(moves) == 0:
return None
# 否则进行搜索
moves = sorted(moves, key=lambda x: alpha_beta_pruning(play_chess(board, player, x), get_opponent(player), depth-1, -1000000, 1000000), reverse=True)
return moves[0]
```
这是一个比较简单的实现,如果要进一步优化,可以考虑加入置换表、启发式搜索等。
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