python把txt中查找到的数字,按顺序替换为(1284, 533), (2416, 130), (1288, 538), (1310, 539), (1318, 533),请给出Python代码
时间: 2023-03-05 21:57:29 浏览: 58
答:代码如下:with open("test.txt") as f:
data = f.read()
data = data.replace("1284", "533").replace("2416", "130").replace("1288", "538").replace("1310", "539").replace("1318", "533")with open("test.txt", "w") as f:
f.write(data)
相关问题
查找txt中的数字,并按顺序替换为(1284, 533), (2416, 130), (1288, 538), (1310, 539), (1318, 533),请给出Python代码
答:这里有一个Python代码的例子:with open('txt.txt', 'r') as f:
data = f.read().replace('(1284, 533)', '(2416, 130)').replace('(1288, 538)', '(1310, 539)').replace('(1318, 533)', '(1318, 533)')with open('txt.txt', 'w') as f:
f.write(data)
python实现二叉树的顺序存储实现二叉树的链接存储 向二叉树中插入节点 从二叉树中删除节点
二叉树的顺序存储实现:
二叉树的顺序存储是指使用数组来存储二叉树,对于完全二叉树,可以按照从上到下、从左到右的顺序依次存储每个节点,对于某个节点的下标为i,则其左子节点的下标为2i,右子节点的下标为2i+1,父节点的下标为i//2。下面是一个简单的例子:
```python
class ArrayBinaryTree:
def __init__(self, max_size):
self.max_size = max_size
self.array = [None] * max_size
self.root = 1
def add(self, value):
if self.array[self.root] is None:
self.array[self.root] = value
else:
i = 1
while i < self.max_size:
if self.array[i] is None:
self.array[i] = value
break
elif value < self.array[i]:
i = 2 * i
else:
i = 2 * i + 1
def preorder_traversal(self, i):
if i < self.max_size and self.array[i] is not None:
print(self.array[i], end=' ')
self.preorder_traversal(2 * i)
self.preorder_traversal(2 * i + 1)
def inorder_traversal(self, i):
if i < self.max_size and self.array[i] is not None:
self.inorder_traversal(2 * i)
print(self.array[i], end=' ')
self.inorder_traversal(2 * i + 1)
def postorder_traversal(self, i):
if i < self.max_size and self.array[i] is not None:
self.postorder_traversal(2 * i)
self.postorder_traversal(2 * i + 1)
print(self.array[i], end=' ')
```
二叉树的链接存储实现:
二叉树的链接存储是指使用节点来存储二叉树,每个节点包含一个数据域和两个指针域,分别指向左子节点和右子节点。下面是一个简单的例子:
```python
class Node:
def __init__(self, value):
self.value = value
self.left = None
self.right = None
class BinaryTree:
def __init__(self):
self.root = None
def add(self, value):
if self.root is None:
self.root = Node(value)
else:
queue = [self.root]
while queue:
node = queue.pop(0)
if node.left is None:
node.left = Node(value)
break
elif node.right is None:
node.right = Node(value)
break
else:
queue.append(node.left)
queue.append(node.right)
def preorder_traversal(self, node):
if node is not None:
print(node.value, end=' ')
self.preorder_traversal(node.left)
self.preorder_traversal(node.right)
def inorder_traversal(self, node):
if node is not None:
self.inorder_traversal(node.left)
print(node.value, end=' ')
self.inorder_traversal(node.right)
def postorder_traversal(self, node):
if node is not None:
self.postorder_traversal(node.left)
self.postorder_traversal(node.right)
print(node.value, end=' ')
```
向二叉树中插入节点:
向二叉树中插入节点需要先找到插入位置,然后将新节点插入到该位置。如果二叉树为空,则新节点为根节点;否则,从根节点开始,如果新节点的值小于当前节点的值,则继续在当前节点的左子树中查找插入位置;否则,在当前节点的右子树中查找插入位置。下面是一个简单的例子:
```python
class Node:
def __init__(self, value):
self.value = value
self.left = None
self.right = None
class BinaryTree:
def __init__(self):
self.root = None
def insert(self, value):
if self.root is None:
self.root = Node(value)
else:
self._insert(self.root, value)
def _insert(self, node, value):
if value < node.value:
if node.left is None:
node.left = Node(value)
else:
self._insert(node.left, value)
else:
if node.right is None:
node.right = Node(value)
else:
self._insert(node.right, value)
```
从二叉树中删除节点:
从二叉树中删除节点需要先找到要删除的节点,然后根据节点的情况进行删除。如果要删除的节点是叶子节点,则直接删除;如果要删除的节点只有一个子节点,则将该子节点替换要删除的节点;如果要删除的节点有两个子节点,则找到该节点的后继节点(即右子树中最小的节点),将后继节点的值赋给要删除的节点,然后删除后继节点。下面是一个简单的例子:
```python
class Node:
def __init__(self, value):
self.value = value
self.left = None
self.right = None
class BinaryTree:
def __init__(self):
self.root = None
def delete(self, value):
self.root = self._delete(self.root, value)
def _delete(self, node, value):
if node is None:
return None
elif value < node.value:
node.left = self._delete(node.left, value)
elif value > node.value:
node.right = self._delete(node.right, value)
else:
if node.left is None and node.right is None:
node = None
elif node.left is None:
node = node.right
elif node.right is None:
node = node.left
else:
min_node = self._find_min(node.right)
node.value = min_node.value
node.right = self._delete(node.right, min_node.value)
return node
def _find_min(self, node):
while node.left is not None:
node = node.left
return node
```
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