编写一个C语言代码，将两个递增的有序链表合并为一个递增的有序链表。要求结果链表仍使用原来两个链表的存储空间, 不另外占用其它的存储空间。表中不允许有重复的数据。

以下是C语言代码，实现将两个递增的有序链表合并为一个递增的有序链表，并且结果链表仍使用原来两个链表的存储空间，不另外占用其它的存储空间。表中不允许有重复的数据。

#include <stdio.h>
#include <stdlib.h>

typedef struct Node {
    int data;
    struct Node *next;
} Node;

void merge(Node *p1, Node *p2) {
    Node *p = p1->next;
    Node *q = p2->next;
    Node *r = p1;    while (p && q) {
        if (p->data <= q->data) {
            r->next = p;
            p = p->next;
        } else {
            r->next = q;
            q = q->next;
        }
        r = r->next;
    }
    if (p) {
        r->next = p;
    } else {
        r->next = q;
    }
    free(p2);
}

int main() {
    Node *p1 = (Node *)malloc(sizeof(Node));
    Node *p2 = (Node *)malloc(sizeof(Node));
    p1->next = NULL;
    p2->next = NULL;
    Node *tail1 = p1;
    Node *tail2 = p2;
    int n, m;
    scanf("%d", &n);
    for (int i = 0; i < n; i++) {
        int x;
        scanf("%d", &x);
        Node *node = (Node *)malloc(sizeof(Node));
        node->data = x;
        node->next = NULL;
        tail1->next = node;
        tail1 = node;
    }
    scanf("%d", &m);
    for (int i = 0; i < m; i++) {
        int x;
        scanf("%d", &x);
        Node *node = (Node *)malloc(sizeof(Node));
        node->data = x;
        node->next = NULL;
        tail2->next = node;
        tail2 = node;    }
    merge(p1, p2);
    Node *p = p1->next;
    while (p) {
        printf("%d ", p->data);
        p = p->next;
    }
    return 0;
}