输入n个字符建立单链表，删除表中重复元素并修改计数，实现单链表字符统计

非常感谢您的提问。以下是实现单链表字符统计的代码：

class Node:
    def __init__(self, data):
        self.data = data
        self.next = None

def create_linked_list(n, chars):
    head = Node(chars[0])
    current = head
    count_dict = {chars[0]: 1}
    for i in range(1, n):
        if chars[i] in count_dict:
            count_dict[chars[i]] += 1
        else:
            count_dict[chars[i]] = 1
            new_node = Node(chars[i])
            current.next = new_node
            current = new_node
    return head, count_dict

def remove_duplicates(head, count_dict):
    current = head
    while current.next is not None:
        if count_dict[current.next.data] > 1:
            count_dict[current.next.data] -= 1
            current.next = current.next.next
        else:
            current = current.next

n = int(input("请输入字符个数："))
chars = input("请输入字符：")
head, count_dict = create_linked_list(n, chars)
remove_duplicates(head, count_dict)

current = head
while current is not None:
    print(current.data, count_dict[current.data])
    current = current.next

希望这个代码能够帮助您解决问题。如果您有任何其他问题，请随时问我。