java实现21点小游戏

下面是一个简单的 Java 代码实现 21 点小游戏：

import java.util.Scanner;

public class Blackjack {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        int total = 0;
        int card1 = (int)(Math.random() * 11) + 1;
        int card2 = (int)(Math.random() * 11) + 1;
        total += card1 + card2;
        System.out.println("Your cards: " + card1 + ", " + card2);
        System.out.println("Total: " + total);
        while (total < 21) {
            System.out.print("Do you want another card? (y/n): ");
            String answer = input.next();
            if (answer.equals("y")) {
                int card = (int)(Math.random() * 11) + 1;
                total += card;
                System.out.println("Your card: " + card);
                System.out.println("Total: " + total);
            } else {
                break;
            }
        }
        if (total == 21) {
            System.out.println("You win!");
        } else if (total > 21) {
            System.out.println("You lose!");
        } else {
            System.out.println("Dealer's turn.");
            int dealerTotal = (int)(Math.random() * 6) + 16;
            System.out.println("Dealer's total: " + dealerTotal);
            if (dealerTotal > 21 || total > dealerTotal) {
                System.out.println("You win!");
            } else {
                System.out.println("You lose!");
            }
        }
    }
}

运行上述代码后，程序会随机发两张牌给玩家，并询问玩家是否需要再要一张牌，直到玩家决定不要牌或者牌的总点数超过了 21 点。然后程序会模拟庄家的回合，庄家的点数是 16 到 21 之间的随机数，然后与玩家的点数进行比较，判断谁获胜。

注意：这只是一个简单的实现，没有考虑到拆牌、保险等复杂规则。