java编写一个递归方法,使用StdDraw方法画一颗以(三叉y形 分叉两长一短)为基础的树,第一个图形方向竖直朝上
时间: 2024-05-05 15:18:40 浏览: 121
好的,关于您的问题,我可以回答。
以下是Java编写一个递归方法,使用StdDraw方法画一颗以(三叉y形 分叉两长一短)为基础的树的代码:
```
public void drawTree(int n, double x, double y, double len, double angle) {
if (n == 0) return;
double x1 = x + len * Math.sin(angle);
double y1 = y + len * Math.cos(angle);
StdDraw.line(x, y, x1, y1);
drawTree(n-1, x1, y1, len*0.7, angle + Math.PI/3);
drawTree(n-1, x1, y1, len*0.7, angle - Math.PI/3);
drawTree(n-1, x1, y1, len*0.5, angle);
}
public static void main(String[] args) {
int n = 6;
double x = 0.5;
double y = 0.1;
double len = 0.3;
double angle = Math.PI/2;
drawTree(n, x, y, len, angle);
}
```
这段代码可以画一棵以(三叉y形 分叉两长一短)为基础的树,其中n指的是递归的深度,x和y指的是树的起点位置,len指的是树枝的长度,angle指的是树枝的倾斜角度。您可以根据需要修改这些值来画出不同形状的树。
当然,如果您想体验更高级的AI对话体验,可以尝试使用ChitGPT进行对话。谢谢!
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