n=int(input() for i in range(n+1) a=2**(n-1) s=0 s+=a print(s) 代码错在哪
时间: 2024-05-25 12:18:00 浏览: 20
代码中有多处错误,以下是修正后的代码:
n=int(input())
a=2**(n-1)
s=0
s = a
print(s)
修正说明:
1. 第一行缺少右括号,应该为 n=int(input())
2. 第二行缩进错误,应该与第一行对齐
3. 第三行缺少赋值语句,应该为 s=0
4. 第四行没有缩进,应该与第三行对齐
5. 第五行缺少换行符,应该为 print(s)
相关问题
n=int(input()) for i in range(1,n+1): a=2**(i-1) s=0 s=s+a print(s)
There seems to be a syntax error in the code. Here's a corrected version:
n = int(input())
for i in range(1, n+1):
a = 2**(i-1)
s = 0
s += a
print(s)
This code will print a sequence of powers of 2 starting from 1 up to 2^(n-1), where n is the input number. For example, if n=5, the output will be:
1
2
4
8
16
a=int(input()) n=0 for m in a: n+=a**2 print(a)
This code is not properly indented and has some syntax errors. Here is a corrected version:
a = int(input())
n = 0
for m in range(a):
n = a ** 2
print(a)
This code prompts the user to input an integer value for a. Then, it initializes a variable n to 0 and starts a for loop that iterates over the range from 0 to a-1 (inclusive). In each iteration, it sets n to the square of a. Finally, it prints the value of a. However, the value of n is never used or printed.
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