sum=0 n=int(input()) for i in range(n): sum+=1/i print(sum)
时间: 2023-12-15 07:06:35 浏览: 27
这段代码存在一个错误,因为在第i次循环中,当i等于0时,分母为0,会导致程序抛出ZeroDivisionError异常。应该从1开始循环,可以做如下修改:
```
sum = 0
n = int(input())
for i in range(1, n+1):
sum += 1/i
print(sum)
```
这样修改后,代码就可以正确地计算和了。
相关问题
sum=0 m,n=int(input()) for i in range(m,n+1): sum += i print(sum)
This code appears to have syntax errors and does not perform any meaningful operation. Here is a corrected version that sums up all the integers between two given numbers:
```
m = int(input("Enter the start number: "))
n = int(input("Enter the end number: "))
sum = 0
for i in range(m, n+1):
sum += i
print("The sum of all integers between", m, "and", n, "is:", sum)
```
This code prompts the user to input the start and end numbers, initializes a sum variable to 0, and then uses a for loop to iterate over all the integers between the start and end numbers (inclusive). On each iteration, the current integer is added to the sum. Finally, the sum is printed out with a descriptive message.
def f(n): sum=0 if n%2!=0: for i in range(1, n+1, 2): sum += 1/i else: for i in range(2, n+1, 2): sum += 1/i return sum n = int(input()) print(f(n))这段代码哪里错了
这段代码并没有明显的错误,但是为了提高代码的可读性和效率,可以进行一些改进:
1. 在定义sum变量时,可以直接赋值为0,不需要使用sum=0。
2. 在判断n的奇偶性时,可以使用n%2==0来判断n是否为偶数,这样就可以避免判断n%2!=0。
3. 在计算sum时,可以使用+=操作符来累加,而不必显式地写出sum=sum+1/i。
4. 可以将for循环中的range函数中的步长改为2,这样可以避免进行奇偶性判断。
改进后的代码如下所示:
```
def f(n):
sum = 0
if n % 2 == 0:
for i in range(2, n + 1, 2):
sum += 1 / i
else:
for i in range(1, n + 1, 2):
sum += 1 / i
return sum
n = int(input())
print(f(n))
```