乌龟吃鱼python

乌龟吃鱼的实现需要在程序中添加判断乌龟和鱼的坐标是否重叠，如果重叠则乌龟吃掉鱼，乌龟体力增加20。具体实现可以在乌龟移动的方法中添加判断语句。代码示例：

class Turtle:
    def __init__(self):
        self.power = 100  # 初始化乌龟体力为100
        self.x = random.randint(0, 10)
        self.y = random.randint(0, 10)

    def move(self):
        new_x = self.x + random.choice([1, 2, -1, -2])
        new_y = self.y + random.choice([1, 2, -1, -2])
        # 判断乌龟是否移动出场景边界
        if new_x < 0:
            self.x = 0
        elif new_x > 10:
            self.x = 10
        else:
            self.x = new_x
        if new_y < 0:
            self.y = 0
        elif new_y > 10:
            self.y = 10
        else:
            self.y = new_y
        self.power -= 1  # 每移动一次，乌龟体力消耗1

    def eat(self):
        self.power += 20  # 乌龟吃掉鱼，乌龟体力增加20
        return True


class Fish:
    def __init__(self):
        self.x = random.randint(0, 10)
        self.y = random.randint(0, 10)

    def move(self):
        new_x = self.x + random.choice([1, -1])
        new_y = self.y + random.choice([1, -1])
        # 判断鱼是否移动出场景边界
        if new_x < 0:
            self.x = 0
        elif new_x > 10:
            self.x = 10
        else:
            self.x = new_x
        if new_y < 0:
            self.y = 0
        elif new_y > 10:
            self.y = 10
        else:
            self.y = new_y


turtle = Turtle()
fish = []
for i in range(10):
    new_fish = Fish()
    fish.append(new_fish)

while True:
    if not len(fish):  # 鱼儿的数量为0游戏结束
        print("Game over: no more fish.")
        break
    if not turtle.power:  # 乌龟体力值为0游戏结束
        print("Game over: turtle is dead.")
        break

    turtle.move()
    for each_fish in fish:
        if each_fish.x == turtle.x and each_fish.y == turtle.y:
            fish.remove(each_fish)
            turtle.eat()
            print("Turtle ate a fish.")
            break
    for each_fish in fish:
        each_fish.move()

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