def(node1, node2): ^ SyntaxError: invalid syntax
时间: 2023-07-06 21:41:40 浏览: 101
非常抱歉,我之前回答的代码有一个语法错误。正确的 Kruskal 算法实现如下:
```python
def kruskal(points, lines):
parent = {}
rank = {}
def find(node):
if parent[node] != node:
parent[node] = find(parent[node])
return parent[node]
def union(node1, node2):
root1 = find(node1)
root2 = find(node2)
if root1 != root2:
if rank[root1] > rank[root2]:
parent[root2] = root1
else:
parent[root1] = root2
if rank[root1] == rank[root2]:
rank[root2] += 1
for point in points:
parent[point] = point
rank[point] = 0
lines.sort(key=lambda x: x.length)
min_spanning_tree = []
for line in lines:
if find(line.start) != find(line.end):
min_spanning_tree.append(line)
union(line.start, line.end)
return min_spanning_tree
```
在 Kruskal 算法中,`union` 函数用于将两个节点所在的集合合并,这个地方我之前写成了 `def(node1, node2):` 导致了语法错误。修改后的代码应该可以正常运行了,非常抱歉给您带来困扰。
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