import sys import os f1 = open(sys.argv[1],'r') f2 = open(sys.argv[2],'r') fout = open(sys.argv[3],'w') dic1 = {} for line1 in f1: tmp1 = line1.strip().split("\t") Gene_ID = tmp1[0] anno = tmp1[1:] dic1[Gene_ID] = anno dic2 = {} for line2 in f2: tmp2 = line2.strip().split("\t") Gene_ID = tmp2[0] gene_name = tmp2[1] dic2[Gene_ID] = gene_name for key in dic2: if key in dic1: fout.write(key + "\t" + dic2[key] + "\t" + dic1[key] + "\n") else: fout.write(key + "\t" + dic2[key] + "\t" + "NA" + "\n" ) f1.close() f2.close() fout.close(),这段代码报错信息为:Traceback (most recent call last): File "/public/work/Personal/wuxu/3_blast/ninanjie/pipei.sh", line 22, in <module> fout.write(key + "\t" + dic2[key] + "\t" + dic1[key] + "\n") TypeError: can only concatenate str (not "list") to str,请修改上述代码
时间: 2024-01-03 07:04:27 浏览: 137
根据报错信息,我们可以看到最后一行出现了TypeError,即字符串与列表不能直接拼接。这是因为dic1的值是一个列表,而我们在拼接时没有指定具体的元素,导致报错。因此,我们需要将dic1[key]改为dic1[key][0],即取出列表中的第一个元素进行拼接。修改后的代码如下:
```
import sys
import os
f1 = open(sys.argv[1],'r')
f2 = open(sys.argv[2],'r')
fout = open(sys.argv[3],'w')
dic1 = {}
for line1 in f1:
tmp1 = line1.strip().split("\t")
Gene_ID = tmp1[0]
anno = tmp1[1:]
dic1[Gene_ID] = anno
dic2 = {}
for line2 in f2:
tmp2 = line2.strip().split("\t")
Gene_ID = tmp2[0]
gene_name = tmp2[1]
dic2[Gene_ID] = gene_name
for key in dic2:
if key in dic1:
fout.write(key + "\t" + dic2[key] + "\t" + dic1[key][0] + "\n")
else:
fout.write(key + "\t" + dic2[key] + "\t" + "NA" + "\n" )
f1.close()
f2.close()
fout.close()
```
阅读全文