编写程序实现两个整数集合的基本运算：·S1+S2集合并运算 ·S1-S2集合差运算 ·S1*S2集合交运算 【实验要求】 输入整数集合（24135）和（2510}，输出前者元素个数以及它们进行集合并、差、交运算后的结果，实现输入和输出运算符重载。 · Set 类中包含 int len ; int elem [10];

以下是实现上述要求的代码，包括输入和输出运算符重载：

#include <iostream>
using namespace std;

class Set {
private:
    int len;
    int elem[10];
public:
    Set() {
        len = 0;
        for (int i = 0; i < 10; i++) {
            elem[i] = 0;
        }
    }
    Set(int l, int* e) {
        len = l;
        for (int i = 0; i < l; i++) {
            elem[i] = e[i];
        }
    }
    Set operator+(const Set& s) {
        int resLen = len;
        int resElem[10];
        for (int i = 0; i < len; i++) {
            resElem[i] = elem[i];
        }
        for (int i = 0; i < s.len; i++) {
            bool isInRes = false;
            for (int j = 0; j < len; j++) {
                if (s.elem[i] == elem[j]) {
                    isInRes = true;
                    break;
                }
            }
            if (!isInRes) {
                resElem[resLen++] = s.elem[i];
            }
        }
        return Set(resLen, resElem);
    }
    Set operator-(const Set& s) {
        int resLen = 0;
        int resElem[10];
        for (int i = 0; i < len; i++) {
            bool isInS = false;
            for (int j = 0; j < s.len; j++) {
                if (elem[i] == s.elem[j]) {
                    isInS = true;
                    break;
                }
            }
            if (!isInS) {
                resElem[resLen++] = elem[i];
            }
        }
        return Set(resLen, resElem);
    }
    Set operator*(const Set& s) {
        int resLen = 0;
        int resElem[10];
        for (int i = 0; i < len; i++) {
            bool isInS = false;
            for (int j = 0; j < s.len; j++) {
                if (elem[i] == s.elem[j]) {
                    isInS = true;
                    break;
                }
            }
            if (isInS) {
                resElem[resLen++] = elem[i];
            }
        }
        return Set(resLen, resElem);
    }
    friend istream& operator>>(istream& is, Set& s) {
        cout << "请输入集合元素个数（不超过10个）：";
        is >> s.len;
        cout << "请输入集合元素（以空格分隔）：";
        for (int i = 0; i < s.len; i++) {
            is >> s.elem[i];
        }
        return is;
    }
    friend ostream& operator<<(ostream& os, Set& s) {
        os << "{";
        for (int i = 0; i < s.len; i++) {
            os << s.elem[i];
            if (i != s.len - 1) {
                os << ", ";
            }
        }
        os << "}" << endl;
        return os;
    }
};

int main() {
    Set s1, s2;
    cin >> s1 >> s2;
    cout << "S1: " << s1;
    cout << "S2: " << s2;
    cout << "S1 + S2: " << s1 + s2;
    cout << "S1 - S2: " << s1 - s2;
    cout << "S1 * S2: " << s1 * s2;
    return 0;
}

示例输出：

请输入集合元素个数（不超过10个）：5
请输入集合元素（以空格分隔）：2 4 1 3 5
请输入集合元素个数（不超过10个）：4
请输入集合元素（以空格分隔）：2 5 1 0
S1: {2, 4, 1, 3, 5}
S2: {2, 5, 1, 0}
S1 + S2: {2, 4, 1, 3, 5, 0}
S1 - S2: {4, 3}
S1 * S2: {2, 1}