c语言四则混合运算代码

以下是一个简单的 C 语言四则混合运算代码示例：

#include<stdio.h>
#include<stdlib.h>
#include<time.h>

int main()
{
    int a, b, c, d, e, f, result;
    char op1, op2;

    srand((unsigned)time(NULL));
    a = rand() % 101;
    b = rand() % 101;
    c = rand() % 101;
    d = rand() % 101;
    e = rand() % 101;
    f = rand() % 101;

    switch (rand() % 4) {
        case 0:
            op1 = '+';
            result = a + b;
            break;
        case 1:
            op1 = '-';
            result = a - b;
            break;
        case 2:
            op1 = '*';
            result = a * b;
            break;
        case 3:
            op1 = '/';
            result = a / b;
            break;
    }

    switch (rand() % 4) {
        case 0:
            op2 = '+';
            result += c;
            break;
        case 1:
            op2 = '-';
            result -= c;
            break;
        case 2:
            op2 = '*';
            result *= c;
            break;
        case 3:
            op2 = '/';
            result /= c;
            break;
    }

    switch (rand() % 4) {
        case 0:
            op2 = '+';
            result += d;
            break;
        case 1:
            op2 = '-';
            result -= d;
            break;
        case 2:
            op2 = '*';
            result *= d;
            break;
        case 3:
            op2 = '/';
            result /= d;
            break;
    }

    switch (rand() % 4) {
        case 0:
            op2 = '+';
            result += e;
            break;
        case 1:
            op2 = '-';
            result -= e;
            break;
        case 2:
            op2 = '*';
            result *= e;
            break;
        case 3:
            op2 = '/';
            result /= e;
            break;
    }

    switch (rand() % 4) {
        case 0:
            op2 = '+';
            result += f;
            break;
        case 1:
            op2 = '-';
            result -= f;
            break;
        case 2:
            op2 = '*';
            result *= f;
            break;
        case 3:
            op2 = '/';
            result /= f;
            break;
    }

    printf("%d %c %d %c %d %c %d %c %d %c %d = %d\n", a, op1, b, op2, c, op2, d, op2, e, op2, f, result);

    return 0;
}

该代码会生成 6 个随机数，分别进行四则混合运算，并输出运算式及结果。