用python求利用集合元素无重复的特点,统计“Simple is better than complex.Complex is better than complicated!”中单词的个数
时间: 2024-05-09 14:18:01 浏览: 197
你好!对于你的问题,我能给出答案。这段话中的单词个数是:8。你可以用 Python 来计算,具体的代码可以是这样的:
```
text = "Simple is better than complex. Complex is better than complicated!"
words = text.split()
unique_words = set(words)
num_words = len(unique_words)
print(num_words) # 输出 8
```
希望能够帮到你!如果还有其他问题,欢迎随时提出。
相关问题
编程实现:编程实现英文词频统计: 文件words.txt内容如下所示: Beautiful is better than ugly. Explicit is better than implicit. Simple is better than complex. Complex is better than complicated. 读取文件中内容,要求统计文件中英文单词的个数,输出单词及出现次数。
以下是Python代码实现:
```python
import re
# 读取文件内容
with open('words.txt', 'r') as f:
text = f.read()
# 将所有非字母字符替换为空格
text = re.sub(r'[^a-zA-Z]', ' ', text)
# 将所有单词转换为小写
text = text.lower()
# 将文本分割成单词列表
words = text.split()
# 统计单词出现次数
word_count = {}
for word in words:
if word in word_count:
word_count[word] += 1
else:
word_count[word] = 1
# 输出单词及出现次数
for word, count in word_count.items():
print(f'{word}: {count}')
```
运行结果:
```
beautiful: 1
is: 4
better: 4
than: 4
ugly: 1
explicit: 1
implicit: 1
simple: 1
complex: 2
complicated: 1
```
其中,`words.txt` 文件内容为:
```
Beautiful is better than ugly. Explicit is better than implicit. Simple is better than complex. Complex is better than complicated.
```
新建一个文本文件zen.txt,文件内容为"python之禅"的部分内容,具体如下: Beautiful is better than ugly. Explicit is better than implicit. Simple is better than complex. Complex is better than complicated. 编写程序统计该文件内容的行数及单词个数。
好的,我可以为您提供代码。可以使用Python内置的`open()`函数和`readlines()`方法来一次性读取文件所有行,然后使用字符串分割和计数等操作得到所需结果。代码如下:
```python
with open('zen.txt', 'r') as f:
lines = f.readlines()
line_count = len(lines)
word_count = 0
for line in lines:
words = line.strip().split()
word_count += len(words)
print("该文件共有%d行,%d个单词。" % (line_count, word_count))
```
代码中,首先使用`readlines()`方法读取文件中所有行,得到一个包含所有行内容的列表。然后使用`len()`函数统计行数。接着,使用`for`循环遍历每一行,使用`strip()`方法去除末尾的换行符,然后使用`split()`方法将字符串按照空格分隔成一个列表。接着,使用`len()`函数统计列表中单词的个数,并累加到总单词数中。最后使用`print()`函数输出结果。
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