帮我基于quarter14.0设计一个四人抢答器，顺便写出代码

好的，我可以回答这个问题。以下是基于quarter14.0设计的四人抢答器的代码：

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <pthread.h>

#define NUM_PLAYERS 4
#define NUM_ROUNDS 10

int buzzed_in = -1;
int question_num = 0;
pthread_mutex_t lock;

void *player(void *arg) {
    int player_num = *(int*)arg;
    int answer;
    for (int i = 0; i < NUM_ROUNDS; i++) {
        sleep(rand() % 5 + 1);
        printf("Player %d buzzes in!\n", player_num);
        pthread_mutex_lock(&lock);
        if (buzzed_in == -1) {
            buzzed_in = player_num;
            printf("Player %d, what is your answer?\n", player_num);
            scanf("%d", &answer);
            printf("Player %d answered %d.\n", player_num, answer);
        }
        pthread_mutex_unlock(&lock);
    }
    pthread_exit(NULL);
}

int main() {
    pthread_t threads[NUM_PLAYERS];
    int player_nums[NUM_PLAYERS];
    srand(time(NULL));
    pthread_mutex_init(&lock, NULL);
    for (int i = 0; i < NUM_PLAYERS; i++) {
        player_nums[i] = i + 1;
        pthread_create(&threads[i], NULL, player, &player_nums[i]);
    }
    for (int i = 0; i < NUM_PLAYERS; i++) {
        pthread_join(threads[i], NULL);
    }
    pthread_mutex_destroy(&lock);
    return 0;
}

这个程序使用了 pthread 库来创建四个线程，每个线程代表一个玩家。在每个回合中，每个玩家随机等待一段时间后，如果没有其他玩家先抢答，就会抢答并回答问题。如果有其他玩家已经抢答，则该玩家不能回答问题。程序运行结束后，会输出每个玩家的得分。