lst =[ ["1", (25, 36)], ["2", (62, 81)], ["3", (22,15), (25, 41)] ] 对列表lst每个子列表中的每个子元组的元素进行相加的和是否大于20。

对于列表lst中的每个子列表，我们可以使用嵌套的循环来计算每个子元组的元素之和，并检查是否大于20。下面是一个实现这个功能的代码示例：

lst = [
        ["1", (25, 36)],
        ["2", (62, 81)],
        ["3", (22, 15), (25, 41)]
    ]

for sublist in lst:
    for subtuple in sublist[1:]:
        # 计算子元组的元素之和
        total = sum(subtuple)
        if total > 20:
            print(f"The sum of elements in {subtuple} is greater than 20.")
        else:
            print(f"The sum of elements in {subtuple} is not greater than 20.")

输出结果将会是：

The sum of elements in (25, 36) is greater than 20.
The sum of elements in (62, 81) is greater than 20.
The sum of elements in (22, 15) is greater than 20.
The sum of elements in (25, 41) is greater than 20.

这段代码遍历了列表lst中的每个子列表，然后针对每个子列表中的每个子元组，计算了它们的元素之和，并根据和是否大于20进行打印输出。