python人机对战井字棋

以下是一个简单的Python人机对战井字棋的示例：

import random

# 初始化棋盘
board = [' '] * 9
# 打印棋盘
def print_board():
    print(board[0] + '|' + board[1] + '|' + board[2])
    print('-')
    print(board[3] + '|' + board[4] + '|' + board[5])
    print('-')
    print(board[6] + '|' + board[7] + '|' + board[8])

# 判断是否有玩家获胜
def check_win(player):
    win_conditions = [
        [0, 1, 2], [3, 4, 5], [6, 7, 8],  # 横向
        [0, 3, 6], [1, 4, 7], [2, 5, 8],  # 纵向
        [0, 4, 8], [2, 4, 6]  # 对角线
    ]
    for condition in win_conditions:
        if board[condition[0]] == board[condition[1]] == board[condition[2]] == player:
            return True
    return False

# 判断是否平局
def check_draw():
    return ' ' not in board

# 玩家落子
def player_move():
    while True:
        move = input("请输入你的落子位置(1-9)：")
        if move.isdigit() and 1 <= int(move) <= 9 and board[int(move) - 1] == ' ':
            board[int(move) - 1] = 'X'
            break
        else:
            print("无效的落子位置，请重新输入！")

# 电脑落子
def computer_move():
    available_moves = [i for i in range(9) if board[i] == ' ']
    move = random.choice(available_moves)
    board[move] = 'O'

# 游戏主循环
def game_loop():
    print("欢迎来到人机对战井字棋游戏！")
    print_board()
    while True:
        player_move()
        print_board()
        if check_win('X'):
            print("恭喜你，你赢了！")
            break
        if check_draw():
            print("平局！")
            break
        computer_move()
        print_board()
        if check_win('O'):
            print("很遗憾，你输了！")
            break
        if check_draw():
            print("平局！")
            break

# 开始游戏
game_loop()