正则表达式转nfa转dfa代码
时间: 2023-07-23 09:02:24 浏览: 237
### 回答1:
正则表达式转换为NFA(非确定有限自动机)可以通过构造Thompson算法实现。代码示例如下:
```python
# 定义NFA状态和边的类
class NFAState:
def __init__(self, label=None):
self.label = label
self.transitions = []
# 定义NFA类
class NFA:
def __init__(self, start_state, accept_states):
self.start_state = start_state
self.accept_states = accept_states
def add_transition(self, state1, input, state2):
state1.transitions.append((input, state2))
# 正则表达式转NFA的函数
def regex_to_nfa(regex):
stack = []
for char in regex:
if char == '*':
# 闭包操作
nfa = stack.pop()
accept_state = NFAState()
nfa.add_transition(accept_state, None, nfa.start_state)
nfa.add_transition(accept_state, None, accept_state)
stack.append(NFA(accept_state, [accept_state]))
elif char == '|':
# 或操作
nfa2 = stack.pop()
nfa1 = stack.pop()
start_state = NFAState()
accept_state = NFAState()
start_state.transitions.append((None, nfa1.start_state))
start_state.transitions.append((None, nfa2.start_state))
nfa1.accept_states[0].transitions.append((None, accept_state))
nfa2.accept_states[0].transitions.append((None, accept_state))
stack.append(NFA(start_state, [accept_state]))
elif char == '.':
# 连接操作
nfa2 = stack.pop()
nfa1 = stack.pop()
nfa1.accept_states[0].transitions.append((None, nfa2.start_state))
stack.append(NFA(nfa1.start_state, nfa2.accept_states))
else:
# 创建单个字符的NFA
accept_state = NFAState()
start_state = NFAState()
start_state.transitions.append((char, accept_state))
stack.append(NFA(start_state, [accept_state]))
return stack.pop()
```
NFA转换为DFA可以使用子集构造算法实现。代码示例如下:
```python
# 定义DFA状态和边的类
class DFAState:
def __init__(self, label=None):
self.label = label
self.transitions = {}
# 定义DFA类
class DFA:
def __init__(self, start_state, accept_states):
self.start_state = start_state
self.accept_states = accept_states
def add_transition(self, state1, input, state2):
state1.transitions[input] = state2
# NFA转DFA的函数
def nfa_to_dfa(nfa):
start_state = DFAState(nfa.start_state.label)
dfa_states = [start_state]
unmarked_states = [start_state]
while unmarked_states:
dfa_state = unmarked_states.pop(0)
transitions = {}
for nfa_state in get_nfa_states(dfa_state, nfa):
for transition in nfa_state.transitions:
input_symbol = transition[0]
next_nfa_state = transition[1]
if input_symbol not in transitions:
transitions[input_symbol] = set()
transitions[input_symbol].add(next_nfa_state)
for input_symbol, next_state_states in transitions.items():
next_state_label = ",".join(sorted([n.label for n in next_state_states]))
next_state = get_or_create_dfa_state(next_state_label, dfa_states)
dfa_state.transitions[input_symbol] = next_state
if next_state not in dfa_states:
dfa_states.append(next_state)
unmarked_states.append(next_state)
accept_states = [s for s in dfa_states if nfa.accept_states[0].label in s.label.split(",")]
return DFA(start_state, accept_states)
# 获取NFA状态的ε闭包
def get_nfa_states(dfa_state, nfa):
nfa_states = []
def get_nfa_states_recursive(nfa_state):
nfa_states.append(nfa_state)
for transition in nfa_state.transitions:
input_symbol = transition[0]
next_nfa_state = transition[1]
if input_symbol is None and next_nfa_state not in nfa_states:
get_nfa_states_recursive(next_nfa_state)
for nfa_state_label in dfa_state.label.split(","):
nfa_state = get_nfa_state_by_label(nfa_state_label, nfa)
get_nfa_states_recursive(nfa_state)
return nfa_states
# 根据NFA状态标签获取NFA状态
def get_nfa_state_by_label(label, nfa):
for state in nfa.accept_states:
if state.label == label:
return state
if nfa.start_state.label == label:
return nfa.start_state
# 根据DFA状态标签获取DFA状态,如果不存在则创建
def get_or_create_dfa_state(label, dfa_states):
for state in dfa_states:
if state.label == label:
return state
return DFAState(label)
```
以上就是将正则表达式转换为NFA,以及将NFA转换为DFA的代码示例。
### 回答2:
正则表达式转NFA主要包括两个步骤:正则表达式转后缀表达式和后缀表达式转NFA。
首先,将给定的正则表达式转换为后缀表达式。可以通过使用栈和运算符优先级来实现。遍历正则表达式的每个字符,如果是操作数,则直接输出到后缀表达式。如果是运算符,则根据优先级进行相应的操作,将栈中优先级大于或等于当前运算符的运算符输出到后缀表达式,再将当前运算符压入栈。当所有字符都被处理完后,将栈中剩余的运算符依次输出到后缀表达式中。
然后,根据后缀表达式构建对应的NFA。可以使用Thompson算法来实现此过程。首先,创建一个空的NFA栈。然后,遍历后缀表达式的每个字符。如果是操作符,如'a'、'b',则创建一个新的NFA,其中有两个状态,一个初始状态和一个接受状态,通过一条连接状态的边进行连接,并将该NFA压入NFA栈。如果是运算符,如'|'、'.'、'*',则从NFA栈中弹出对应的NFA,并根据运算符创建新的NFA,并将该NFA压入NFA栈。
最后,将得到的NFA转换为DFA。可以使用子集构造算法来实现此过程。首先,将NFA的初始状态作为DFA的初始状态,并计算该状态的ε-闭包。然后,将ε-闭包作为DFA的一个状态,如果该状态中包含NFA的接受状态,则将该状态标记为接受状态。接着,对于每个输入符号,计算该输入符号在当前状态下,通过ε-闭包能够到达的NFA状态,并将其作为DFA的一个新状态。重复以上步骤,直到所有的DFA状态都被生成。最终得到的DFA即为所求。
以上是正则表达式转换为NFA再转换为DFA的基本过程。可以根据具体的编程语言和数据结构进行具体的实现。
### 回答3:
正则表达式转NFA(Nondeterministic Finite Automaton)的过程可以通过使用Thompson算法来实现,以下是一个简单的Python代码示例:
```python
class State:
def __init__(self, label=None):
self.label = label
self.edges = []
class NFA:
def __init__(self, start=None, end=None):
self.start = start
self.end = end
def regex_to_nfa(regex):
stack = []
for char in regex:
if char == '.':
nfa2 = stack.pop()
nfa1 = stack.pop()
nfa1.end.edges.append(nfa2.start)
stack.append(NFA(nfa1.start, nfa2.end))
elif char == '|':
nfa2 = stack.pop()
nfa1 = stack.pop()
start = State()
start.edges.extend([nfa1.start, nfa2.start])
end = State()
nfa1.end.edges.append(end)
nfa2.end.edges.append(end)
stack.append(NFA(start, end))
elif char == '*':
nfa = stack.pop()
start = State()
end = State()
start.edges.extend([nfa.start, end])
nfa.end.edges.extend([nfa.start, end])
stack.append(NFA(start, end))
else:
start = State()
end = State()
start.edges.append(end)
stack.append(NFA(start, end))
return stack.pop()
def nfa_to_dfa(nfa):
dfa_start = State()
dfa = NFA(dfa_start)
dfa_states = [dfa_start]
state_map = {}
state_queue = [dfa_start]
while len(state_queue) > 0:
current_state = state_queue.pop(0)
state_map[current_state] = {}
for char in nfa.alphabet:
new_state = State()
state_map[current_state][char] = new_state
for nfa_state in current_state:
if nfa_state.label == char:
new_state.append(nfa_state.edges)
for edge in nfa_state.edges:
if edge not in dfa_states:
state_queue.append(edge)
dfa_states.append(edge)
return dfa
regex = "(ab)*c"
nfa = regex_to_nfa(regex)
dfa = nfa_to_dfa(nfa)
```
以上代码实现了将正则表达式转化为NFA,以及将NFA转化为DFA的过程。在这个示例中,我们使用Thompson算法将正则表达式转换为NFA,并使用子集构造法将NFA转换为DFA。最终得到的DFA可以用于模式匹配和字符串匹配等应用。该示例代码仅为简化版本,实际实现中可能会有更多的细节和优化。
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