java猜数字代码实现

好的，以下是一个简单的 Java 猜数字游戏的代码实现：

import java.util.Random;
import java.util.Scanner;

public class GuessNumber {
    public static void main(String[] args) {
        Random random = new Random();
        int numberToGuess = random.nextInt(100) + 1;
        int numberOfTries = 0;
        Scanner input = new Scanner(System.in);
        int guess;
        boolean win = false;

        while (numberOfTries < 10) {
            System.out.print("Guess a number between 1 and 100: ");
            guess = input.nextInt();
            numberOfTries++;

            if (guess == numberToGuess) {
                System.out.println("Congratulations! You guessed the number in " + numberOfTries + " tries!");
                win = true;
                break;
            } else if (guess < numberToGuess) {
                System.out.println("The number is higher than " + guess + ". Try again.");
            } else {
                System.out.println("The number is lower than " + guess + ". Try again.");
            }
        }

        if (!win) {
            System.out.println("Sorry, you ran out of tries. The number was " + numberToGuess + ".");
        }
    }
}

这个程序会随机生成一个 1 到 100 的整数，然后让用户在 10 次机会内猜出这个数字。如果用户猜对了，程序会输出猜对的次数并结束游戏；如果用户用完了所有机会还没有猜对，程序会输出正确答案并结束游戏。