expansion ratio
时间: 2024-04-24 18:26:40 浏览: 14
扩张比(expansion ratio)是指物体在受力作用下的尺寸变化比例。它可以用来描述物体在某个方向上的线性扩张或收缩程度。扩张比的计算公式为:
扩张比 = (最终尺寸 - 初始尺寸)/ 初始尺寸
其中,最终尺寸是物体在受力后的尺寸,初始尺寸是物体在受力前的尺寸。扩张比可以用百分数或小数表示,正值表示扩张,负值表示收缩。
相关问题
def _make_denseblock(self, block, blocks): layers = [] for i in range(blocks): # Currently we fix the expansion ratio as the default value layers.append(block(self.inplanes, growthRate=self.growthRate, dropRate=self.dropRate)) self.inplanes += self.growthRate return nn.Sequential(*layers) 这段代码意思
这段代码实现了一个 Dense Block 的生成函数 `_make_denseblock`,它接受两个参数:`block` 表示要使用的基础网络层,`blocks` 表示要生成的 Dense Block 的个数。函数返回一个由 Dense Block 中的所有网络层按顺序组成的 PyTorch 的 `nn.Sequential` 对象。
在函数中,首先定义了一个空列表 `layers`,然后通过一个循环来生成 Dense Block 中的每个网络层。每次循环中,都会调用 `block` 函数来生成一个网络层,并将其添加到 `layers` 列表中。其中,`self.inplanes` 表示当前输入的通道数,`self.growthRate` 表示每个网络层要增加的通道数,`self.dropRate` 表示每个网络层的 dropout 概率。在每次循环结束后,都会将 `self.inplanes` 更新为当前的通道数,这样下一个网络层的输入通道数就是上一个网络层的输出通道数。
最后,函数返回一个 `nn.Sequential` 对象,其中包含了所有生成的网络层。这个对象可以被视为一个整体,方便在后续的神经网络模型中使用。
Non-terminating decimal expansion; no exact representable decimal result 两个double 类型相除 java
Non-terminating decimal expansion refers to a situation where the decimal representation of a mathematical fraction, when expressed as a floating-point number, does not have an exact representation in binary format used by computers. This occurs when the division of two numbers results in a non-terminating or recurring decimal pattern that cannot be represented precisely with the finite precision of a double data type, which has a limited number of bits for storing fractional parts.
In Java, specifically with the `double` type, this happens because the IEEE 754 standard used for floating-point arithmetic reserves some bits for the exponent and mantissa, leading to a finite set of possible values. When dividing two `double` numbers with an exact ratio that cannot be expressed as a simple fraction with integer coefficients, the result will be approximated based on these limitations.
For example, consider the division of 1 by 3 in decimal form, which is an infinite repeating decimal (0.3333...). If you try to store this value in a `double`, you will get an approximation like 0.3333333333333333, and if you perform calculations involving this number repeatedly, the sequence may start to diverge slightly due to rounding errors.
When such a case arises, it's important to handle the potential for inaccuracies in your code. You can use libraries like BigDecimal for more precise decimal arithmetic or implement custom algorithms to manage the precision issues.
相关推荐
![pdf](https://img-home.csdnimg.cn/images/20210720083512.png)
![pdf](https://img-home.csdnimg.cn/images/20210720083512.png)
![pdf](https://img-home.csdnimg.cn/images/20210720083512.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![zip](https://img-home.csdnimg.cn/images/20210720083736.png)
![pdf](https://img-home.csdnimg.cn/images/20210720083512.png)