光谱基线校正算法 C#
时间: 2023-12-06 22:37:43 浏览: 209
根据提供的引用内容,我们可以了解到一种结合导数谱峰检测与Whittaker平滑器的基线校正算法。这种算法可以用于光谱基线校正,下面是一个C#的实现示例:
```csharp
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using MathNet.Numerics.LinearAlgebra;
using MathNet.Numerics.LinearAlgebra.Double;
namespace BaselineCorrection
{
class Program
{
static void Main(string[] args)
{
// 读取光谱数据
double[] x = new double[] { 1, 2, 3, 4, 5 };
double[] y = new double[] { 1.2, 1.5, 1.8, 2.1, 1.9 };
// 计算一阶导数
double[] dy = new double[y.Length];
for (int i = 0; i < y.Length - 1; i++)
{
dy[i] = y[i + 1] - y[i];
}
dy[y.Length - 1] = dy[y.Length - 2];
// 计算二阶导数
double[] ddy = new double[dy.Length];
for (int i = 0; i < dy.Length - 1; i++)
{
ddy[i] = dy[i + 1] - dy[i];
}
ddy[dy.Length - 1] = ddy[dy.Length - 2];
// 寻找谷点
List<int> valleyIndex = new List<int>();
for (int i = 1; i < ddy.Length - 1; i++)
{
if (ddy[i] < 0 && ddy[i - 1] > 0 && ddy[i + 1] > 0)
{
valleyIndex.Add(i);
}
}
// 寻找峰点
List<int> peakIndex = new List<int>();
for (int i = 1; i < ddy.Length - 1; i++)
{
if (ddy[i] > 0 && ddy[i - 1] < 0 && ddy[i + 1] < 0)
{
peakIndex.Add(i);
}
}
// 计算Whittaker平滑器系数
double lambda = 100;
double[] w = new double[y.Length];
for (int i = 1; i < y.Length - 1; i++)
{
w[i] = 1 / (1 + lambda * Math.Pow(dy[i], 2));
}
// 构造矩阵
Matrix<double> A = DenseMatrix.Create(y.Length, N + 1, (i, j) => Math.Pow(x[i], j));
Vector<double> b = DenseVector.OfArray(y);
// 求解线性方程组
Vector<double> c = A.Transpose() * (DiagonalMatrix.OfDiagonal(w) * A);
c = c.Inverse() * A.Transpose() * (DiagonalMatrix.OfDiagonal(w) * b);
// 计算拟合曲线
double[] fit = new double[y.Length];
for (int i = 0; i < y.Length; i++)
{
for (int j = 0; j < N + 1; j++)
{
fit[i] += c[j] * Math.Pow(x[i], j);
}
}
// 计算基线
double[] baseline = new double[y.Length];
for (int i = 0; i < y.Length; i++)
{
baseline[i] = y[i] - fit[i];
}
// 输出基线校正后的光谱数据
for (int i = 0; i < y.Length; i++)
{
Console.WriteLine("{0}\t{1}\t{2}", x[i], y[i], baseline[i]);
}
}
}
}
```
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