def fold_paper(length, width, times): if times == 0: return length, width half_length = length // 2 half_width = width // 2 if length % 2 == 1: half_length += 1 if width % 2 == 1: half_width += 1 return fold_paper(half_length, width, times - 1), fold_paper(length, half_width, times - 1) if __name__ == '__main__': length = int(input("请输入长方形的长度：")) width = int(input("请输入长方形的宽度：")) times = int(input("请输入对折的次数：")) final_length, final_width = fold_paper(length, width, times) print("最终的长和宽分别为：{}, {}".format(final_length, final_width)) if final_length > final_width: print("从大到小输出：{}, {}".format(final_length, final_width)) else: print("从大到小输出：{}, {}".format(final_width, final_length))简化代码

可以将递归函数中的两个返回值改为一个元组类型，来简化程序：

def fold_paper(length, width, times):
    if times == 0:
        return length, width
    half_length = (length + 1) // 2
    half_width = (width + 1) // 2
    return fold_paper(half_length, width, times - 1)[0], fold_paper(length, half_width, times - 1)[1]

if __name__ == '__main__':
    length = int(input("请输入长方形的长度："))
    width = int(input("请输入长方形的宽度："))
    times = int(input("请输入对折的次数："))
    final_length, final_width = fold_paper(length, width, times)
    print("最终的长和宽分别为：{}, {}".format(final_length, final_width))
    if final_length > final_width:
        print("从大到小输出：{}, {}".format(final_length, final_width))
    else:
        print("从大到小输出：{}, {}".format(final_width, final_length))

这样程序更加简洁。