用C++写一个A*寻路算法
时间: 2023-05-15 20:07:24 浏览: 148
好的,以下是一个简单的C语言实现的A*寻路算法:
```c
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#define ROW 5
#define COL 5
typedef struct {
int x, y;
} Point;
typedef struct {
Point parent;
int f, g, h;
} Node;
Node map[ROW][COL];
Point start, end;
bool is_valid(int x, int y) {
return x >= 0 && x < ROW && y >= 0 && y < COL;
}
bool is_obstacle(int x, int y) {
return map[x][y].f == -1;
}
int heuristic(int x, int y) {
return abs(x - end.x) + abs(y - end.y);
}
void print_path() {
Point path[ROW * COL];
int count = 0;
Point current = end;
while (current.x != start.x || current.y != start.y) {
path[count++] = current;
current = map[current.x][current.y].parent;
}
path[count++] = start;
printf("Path: ");
for (int i = count - 1; i >= 0; i--) {
printf("(%d, %d) ", path[i].x, path[i].y);
}
printf("\n");
}
void a_star() {
int dx[8] = {-1, -1, 0, 1, 1, 1, 0, -1};
int dy[8] = {0, 1, 1, 1, 0, -1, -1, -1};
map[start.x][start.y].f = 0;
map[start.x][start.y].g = 0;
map[start.x][start.y].h = heuristic(start.x, start.y);
Node open_set[ROW * COL];
int open_set_size = 1;
open_set[0] = map[start.x][start.y];
while (open_set_size > 0) {
int current_index = 0;
for (int i = 1; i < open_set_size; i++) {
if (open_set[i].f < open_set[current_index].f) {
current_index = i;
}
}
Node current = open_set[current_index];
if (current.parent.x == end.x && current.parent.y == end.y) {
print_path();
return;
}
open_set[current_index] = open_set[open_set_size - 1];
open_set_size--;
for (int i = 0; i < 8; i++) {
int new_x = current.parent.x + dx[i];
int new_y = current.parent.y + dy[i];
if (!is_valid(new_x, new_y) || is_obstacle(new_x, new_y)) {
continue;
}
int new_g = current.g + 1;
int new_h = heuristic(new_x, new_y);
int new_f = new_g + new_h;
if (map[new_x][new_y].f == -2 || new_f < map[new_x][new_y].f) {
map[new_x][new_y].parent = current.parent;
map[new_x][new_y].f = new_f;
map[new_x][new_y].g = new_g;
map[new_x][new_y].h = new_h;
if (map[new_x][new_y].f == -2) {
open_set[open_set_size++] = map[new_x][new_y];
}
}
}
}
printf("No path found!\n");
}
int main() {
// initialize map
for (int i = 0; i < ROW; i++) {
for (int j = 0; j < COL; j++) {
map[i][j].parent.x = i;
map[i][j].parent.y = j;
map[i][j].f = -2;
map[i][j].g = -2;
map[i][j].h = -2;
}
}
// set obstacles
map[1][1].f = -1;
map[1][2].f = -1;
map[1][3].f = -1;
map[2][3].f = -1;
map[3][3].f = -1;
map[3][2].f = -1;
// set start and end points
start.x = 0;
start.y = 0;
end.x = 4;
end.y = 4;
// run A* algorithm
a_star();
return 0;
}
```
这个程序实现了一个简单的A*寻路算法,可以在一个5x5的地图上找到从起点到终点的最短路径。其中,-1表示障碍物,-2表示未访问过的节点,其它数字表示已访问过的节点的f值。
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