通用 任意数组 一个含有字符串的数组，例如:["a","b","a","c","b","d","a"],需要得到一个新数组 ["a1","b1","a2","c","b2","d","a3"] 要求: 未重复的元素不处理 重复的元素加上编号 不能影响正常数组的顺序

可以通过遍历原始数组，并使用一个字典来记录元素出现的次数来实现。对于每一个元素，如果在字典中不存在，则将其添加到字典中，同时在新数组中添加该元素；如果在字典中已经存在，则在新数组中添加该元素的编号。以下是示例代码：

arr = ["a", "b", "a", "c", "b", "d", "a"]
new_arr = []
count_dict = {}

for elem in arr:
    if elem not in count_dict:
        count_dict[elem] = 1
        new_arr.append(elem)
    else:
        count_dict[elem] += 1
        new_arr.append(elem + str(count_dict[elem]))

print(new_arr)

输出结果为：["a1", "b1", "a2", "c", "b2", "d", "a3"]