请使用单链表实现通讯录，每个链表节点包含name、address、phone这3个信息。（1）请写一个create（）函数存储3个人的通讯信息； ​ （2）请遍历输出问题（1）创建的通讯录链表； ​

以下是使用单链表实现通讯录的代码，其中包含了create()函数和遍历输出通讯录链表的函数display()：

#include <iostream>
using namespace std;

// 定义通讯录节点结构体
struct Person {
    string name;
    string address;
    string phone;
    Person* next;
};

// 创建通讯录链表
void create(Person*& head) {
    // 创建3个节点
    Person* p1 = new Person;
    p1->name = "Alice";
    p1->address = "123 Main St.";
    p1->phone = "555-1234";
    p1->next = NULL;

    Person* p2 = new Person;
    p2->name = "Bob";
    p2->address = "456 Elm St.";
    p2->phone = "555-5678";
    p2->next = NULL;

    Person* p3 = new Person;
    p3->name = "Charlie";
    p3->address = "789 Oak St.";
    p3->phone = "555-9012";
    p3->next = NULL;

    // 将3个节点连接成链表
    head = p1;
    p1->next = p2;
    p2->next = p3;
}

// 遍历输出通讯录链表
void display(Person* head) {
    while (head != NULL) {
        cout << "Name: " << head->name << endl;
        cout << "Address: " << head->address << endl;
        cout << "Phone: " << head->phone << endl << endl;
        head = head->next;
    }
}

int main() {
    Person* head = NULL;
    create(head);
    display(head);
    return 0;
}

运行结果：

Name: Alice
Address: 123 Main St.
Phone: 555-1234

Name: Bob
Address: 456 Elm St.
Phone: 555-5678

Name: Charlie
Address: 789 Oak St.
Phone: 555-9012