2. 简答题 写一个雇员类（姓名，年龄，薪水），一个经理类（姓名，年龄，薪水，管理的人数），每个雇员有管理他的经理，每个经理有管理的员工，在测试内中通过雇员“李四”找到其经理“张三”的信息；通过经理“张三”找到他管理的所有雇员的信息。

为了实现这个需求，我们可以创建两个类：`Employee` 和 `Manager`，并使用嵌套类的关系来代表管理层次结构。这里是一个简单的Python实现示例：

class Employee:
    def __init__(self, name, age, salary, manager=None):
        self.name = name
        self.age = age
        self.salary = salary
        self.manager = manager

    def get_manager(self):
        return self.manager

    @classmethod
    def find_employee_by_name(cls, employee_name, manager_name):
        # 这里只是一个简化的查找示例，实际应用中需要存储所有员工数据
        for e in cls.all_employees:
            if e.name == employee_name and e.get_manager() is not None and e.get_manager().name == manager_name:
                return e
        return None


class Manager(Employee):
    all_employees = []

    def __init__(self, name, age, salary, num_employees=0):
        super().__init__(name, age, salary)
        self.num_employees = num_employees
        self.employees = []

    def add_employee(self, employee):
        self.employees.append(employee)
        employee.manager = self
        Manager.all_employees.append(employee)

    def get_employee_info(self):
        return [e for e in self.employees]

# 示例测试
manager_zhangsan = Manager("张三", 35, 8000, 2)
employee_liisi = Employee("李四", 28, 6000, manager_zhangsan)
manager_zhangsan.add_employee(employee_liisi)

# 查找员工信息
employee_info = Employee.find_employee_by_name("李四", "张三")
if employee_info:
    print(f"员工{employee_info.name}的经理是{employee_info.manager.name}")
else:
    print("找不到匹配的员工")

# 查找经理信息
all_employees = manager_zhangsan.get_employee_info()
print(f"经理{manager_zhangsan.name}管理的员工信息:")
for e in all_employees:
    print(e.name)