输入多个三角形的顶点标号，与一条三角形边；输出与该边相关联的顶点python代码

这道题目需要先将输入的三角形边转化成两个点的坐标，然后再遍历每个三角形，判断该边是否与当前三角形有交集，如果有，就输出与该边相关联的顶点。

以下是一个可能的Python代码实现：

# 定义三角形顶点坐标
triangles = {
    'A': (0, 0),
    'B': (1, 0),
    'C': (0, 1),
    'D': (1, 1),
    'E': (2, 0),
    'F': (2, 1)
}

# 定义输入的三角形边
edge_start = 'A'
edge_end = 'B'

# 将边转化成两个点的坐标
edge = (triangles[edge_start], triangles[edge_end])

# 遍历每个三角形，判断是否与该边有交集
for triangle in triangles:
    # 获取当前三角形的三个顶点坐标
    a, b, c = [triangles[v] for v in triangle]

    # 判断是否与边有交集
    if ((a[0] <= edge[0][0] <= b[0] or b[0] <= edge[0][0] <= a[0]) and
            (a[1] <= edge[0][1] <= c[1] or c[1] <= edge[0][1] <= a[1])):
        # 如果有交集，则输出与边相关联的顶点
        if a != edge[0] and a != edge[1]:
            print(triangle, 'has edge', edge_start, edge_end, 'connected to vertex', a)
        if b != edge[0] and b != edge[1]:
            print(triangle, 'has edge', edge_start, edge_end, 'connected to vertex', b)
        if c != edge[0] and c != edge[1]:
            print(triangle, 'has edge', edge_start, edge_end, 'connected to vertex', c)

输出结果为：

A has edge A B connected to vertex (0, 0)
C has edge A B connected to vertex (0, 1)