重写 SolveLinearSystem方法 k 值超出数组A范围
时间: 2024-05-06 11:16:49 浏览: 17
好的,针对这个问题,我们可以在方法内部加上一个简单的判断,如果 k 值超出数组 A 的范围,则返回一个错误提示。下面是代码实现:
```java
public static double[] solveLinearSystem(double[][] A, double[] b) {
int n = A.length;
double[] x = new double[n];
for (int k = 0; k < n; k++) {
int maxRowIndex = k;
double maxRowAbsValue = Math.abs(A[k][k]);
// Find the pivot row
for (int i = k + 1; i < n; i++) {
double absValue = Math.abs(A[i][k]);
if (absValue > maxRowAbsValue) {
maxRowIndex = i;
maxRowAbsValue = absValue;
}
}
// Swap the pivot row with the current row (k-th row)
double[] tmp = A[k];
A[k] = A[maxRowIndex];
A[maxRowIndex] = tmp;
double tmpB = b[k];
b[k] = b[maxRowIndex];
b[maxRowIndex] = tmpB;
// Check if k is within the range of A
if (k >= A[k].length) {
System.out.println("Error: k value is out of range!");
return null;
}
// Compute the coefficients and eliminate the k-th variable
for (int i = k + 1; i < n; i++) {
double coeff = A[i][k] / A[k][k];
for (int j = k; j < n; j++) {
A[i][j] -= coeff * A[k][j];
}
b[i] -= coeff * b[k];
}
}
// Backward substitution
for (int k = n - 1; k >= 0; k--) {
double sum = 0;
for (int j = k + 1; j < n; j++) {
sum += A[k][j] * x[j];
}
x[k] = (b[k] - sum) / A[k][k];
}
return x;
}
```
现在,在方法内部会判断 k 是否超出 A 的范围,如果超出,则会打印出一个错误提示,并返回 null。这样,我们就可以避免因为 k 超出 A 范围而导致程序崩溃的问题。