我需要c语言【问题描述】 编制一个能演示执行集合的并、交和差运算的程序。 【基本要求】 (集合的元素限定为小写字母字符「a..’2]。 (2 演示程序以用户和计算机的对话方式执行。
时间: 2024-05-02 12:16:29 浏览: 98
以下是一个简单的C语言程序,用于演示集合的并、交和差运算:
```
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX_SET_SIZE 26
typedef struct {
char elements[MAX_SET_SIZE];
int size;
} Set;
Set union_set(Set set1, Set set2) {
Set result = { 0 };
int i;
for (i = 0; i < set1.size; i++) {
result.elements[result.size++] = set1.elements[i];
}
for (i = 0; i < set2.size; i++) {
if (!strchr(result.elements, set2.elements[i])) {
result.elements[result.size++] = set2.elements[i];
}
}
return result;
}
Set intersection_set(Set set1, Set set2) {
Set result = { 0 };
int i;
for (i = 0; i < set1.size; i++) {
if (strchr(set2.elements, set1.elements[i])) {
result.elements[result.size++] = set1.elements[i];
}
}
return result;
}
Set difference_set(Set set1, Set set2) {
Set result = { 0 };
int i;
for (i = 0; i < set1.size; i++) {
if (!strchr(set2.elements, set1.elements[i])) {
result.elements[result.size++] = set1.elements[i];
}
}
return result;
}
int main() {
Set set1 = { "abc", 3 };
Set set2 = { "cde", 3 };
Set result;
char operation;
do {
printf("Enter operation (u for union, i for intersection, d for difference, or q to quit): ");
scanf(" %c", &operation);
switch (operation) {
case 'u':
result = union_set(set1, set2);
printf("Union: ");
break;
case 'i':
result = intersection_set(set1, set2);
printf("Intersection: ");
break;
case 'd':
result = difference_set(set1, set2);
printf("Difference: ");
break;
case 'q':
exit(0);
default:
printf("Invalid operation\n");
continue;
}
for (int i = 0; i < result.size; i++) {
printf("%c", result.elements[i]);
}
printf("\n");
} while (1);
return 0;
}
```
该程序使用结构体表示一个集合,包含一个字符数组和一个整数表示集合的大小。并、交和差运算分别由三个函数实现。在主函数中,程序使用一个循环来等待用户输入运算类型,然后调用相应的函数并输出结果。用户可以不断进行运算,直到输入“q”退出程序。
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