生成一个求解一元三次方程的C语言代码

以下是求解一元三次方程的C语言代码：

#include <stdio.h>
#include <math.h>

int main()
{
double a, b, c, d;
double x1, x2, x3;
printf("请输入一元三次方程的系数a、b、c：\n");
scanf("%lf %lf %lf", &a, &b, &c);
d = b * b - 3 * a * c;
if (d < 0)
{
printf("方程无实数解。\n");
}
else if (d == 0)
{
x1 = x2 = x3 = -b / (3 * a);
printf("方程的三个实数解为：x1=x2=x3=%lf。\n", x1);
}
else
{
x1 = (-b + sqrt(d)) / (3 * a);
x2 = (-b - sqrt(d)) / (3 * a);
x3 = (2 * b + sqrt(d)) / (3 * a);
printf("方程的三个实数解为：x1=%lf，x2=%lf，x3=%lf。\n", x1, x2, x3);
}
return 0;
}