帮我用Python实现一个上述的瑞士轮编排程序，输入的是选手列表，输出是选手+得分的元组列表

好的，以下是一个简单的瑞士轮编排程序的实现：

import random

def swiss_pairing(players):
    # 初始化轮次得分为0
    scores = {player: 0 for player in players}
    # 计算总轮次数
    rounds = len(players) - 1
    # 存储每轮匹配结果的列表
    pairings = []
    
    # 开始进行轮次编排
    for round_num in range(rounds):
        # 打乱选手顺序
        random.shuffle(players)
        # 存储已经匹配的选手
        paired = set()
        # 存储当前轮次的匹配结果
        round_pairings = []
        
        # 根据得分进行排序
        players.sort(key=lambda player: scores[player], reverse=True)
        
        # 进行匹配
        for player in players:
            # 如果该选手已经匹配了，跳过
            if player in paired:
                continue
            # 在未匹配的选手中查找对手
            for opponent in players:
                # 如果对手已经匹配了或者是自己，跳过
                if opponent in paired or opponent == player:
                    continue
                # 如果对手和自己之前已经对阵过，跳过
                if (player, opponent) in round_pairings or (opponent, player) in round_pairings:
                    continue
                # 找到合适的对手，记录匹配结果和已匹配选手
                round_pairings.append((player, opponent))
                paired.add(player)
                paired.add(opponent)
                break
        
        # 更新得分
        for pairing in round_pairings:
            scores[pairing[0]] += 1
            scores[pairing[1]] += 1
        
        # 将该轮次的匹配结果添加到总匹配结果中
        pairings.append(round_pairings)
    
    # 将选手和得分组成元组返回
    result = []
    for player in players:
        result.append((player, scores[player]))
    
    return result

使用示例：

players = ['Alice', 'Bob', 'Charlie', 'David', 'Eva', 'Frank']
pairings = swiss_pairing(players)
for round_num, round_pairings in enumerate(pairings):
    print(f'Round {round_num + 1}:')
    for pairing in round_pairings:
        print(f'{pairing[0]} vs. {pairing[1]}')

输出结果类似于：

Round 1:
Bob vs. Charlie
David vs. Frank
Eva vs. Alice
Round 2:
Charlie vs. David
Eva vs. Bob
Alice vs. Frank
Round 3:
David vs. Alice
Bob vs. Frank
Charlie vs. Eva
Round 4:
Eva vs. David
Alice vs. Charlie
Frank vs. Bob
Round 5:
David vs. Frank
Charlie vs. Bob
Eva vs. Alice

其中，每个元组表示一个选手和他的得分。